Answer:
(x+8,y-6)
Step-by-step explanation:
it's the number of values that x and y differ
Answer:
wala kang jowa..........................
Answer:
67
Step-by-step explanation: Given the quadratic equation $z^2 + bz + c = 0$, Vieta's formulas tell us the sum of the roots is $-b$, and the product of the roots is $c$. Thus,
\[-b = (-7 + 2i) + (-7 - 2i) = -14,\]so $b = 14.$
Also,
\[c = (-7 + 2i)(-7 - 2i) = (-7)^2 - (2i)^2 = 49 + 4 = 53.\]Therefore, we have $b+c = \boxed{67}$.
There are many other solutions to this problem. You might have started with the factored form $(z - (-7 + 2i))(z - (-7 - 2i)),$ or even thought about the quadratic formula.
This is the aops answer :)
Answer:
Translate right 7 units (x+7)
Reflect over x-axis (-y) and translate down 6 units (-y - 6)
I believe the X-coordinate of the midpoint would be (0.5,-0.5)
