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adell [148]
3 years ago
14

What is the use of consonant in QBASIC ? Answer me in short and easy answer.​

Computers and Technology
1 answer:
Digiron [165]3 years ago
3 0

Answer:

See Explanation

Explanation:

I'll assume the question is about the use of constants in QBasic because consonants do not have any special function or usage in QBasic.

In simple terms: In QBasic, constants are used to represent elements that do not change in value during program execution.

Take for instance, you intend to use \pi in your program.

Its value is \pi = 3.142

So, 3.142 will always be a constant in your program. One of the ways it can be used in a program is:

10 LET PI = 3.142

<em>The above represents a numeric constant. QBasic also have string constants.</em>

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Hope this helps :)
3 0
3 years ago
You and a few friends are having a meal at a pizza restaurant, and the server has just given you the bill. Write a function that
cestrela7 [59]

Answer:

How to calculate the total cost of the meal

For bill inclusive of tax, cost1=cost*(1+tax percentage)

For bill inclusive of tax and tip, cost2=cost1*(1+tip percentage)

Meal cost =(pizza cost*(1+tax percentage))*(1+tip percentage)

Now how to calculate the cost per person

cost per person=meal cost/ number of people.

C language code to solve the above problem is given below with appropriate comments for explanation

Explanation:

#include<stdio.h>

float split_bill(int cost,float tax)

{

//Declaring number of people as int

int number;

//Prompting for number of people

printf("Enter number of people ");

scanf("%d",&number);

//Declaring tip percentage as float

float tip_percent;

//Prompting for tip percentage

printf("Enter tip percentage between 0 and 1 ");

scanf("%f",&tip_percent);

//Calculating total meal cost

float meal=(((float)cost)*(1+tax))*(1+tip_percent);

//Printing total cost of meal

printf("Total cost of meal: %0.2f ",meal);

//Calculating cost per person

float cost_per_person=meal/number;

//Returning cost per person to main function

return cost_per_person;

}

int main()

{

//Declaring pizza cost as int and tax percentage as float

int pizza_cost;

float tax_percent;

//Prompting user for pizza cost

printf("Enter billing amount of pizza ");

scanf("%d",&pizza_cost);

//Prompting user for tax percentage

printf("Enter tax percentage between 0 and 1 ");

scanf("%f",&tax_percent);

//Printing the cost per person by calling the function split_bill

printf("Total cost per person is: %0.2f ",split_bill(pizza_cost,tax_percent));

return 0;

}

8 0
3 years ago
Anchor hyperlink to position the cursor to the section called sisters? i need a code pls
enot [183]

use an anchor tag(<a>This is an anchor tag</a>) and use the href attribute and set it's destination to the section element who's id or class is "sisters".



Example:

<a href="#Sisters">Click Here!</a>

then you can add this somewhere on the document.

<section id="Sisters">Hello World!</section>

7 0
3 years ago
Which kind of file would be hurt most by lossy compression algorithm
Eduardwww [97]

Answer: an audio file containing speech

Explanation:

8 0
3 years ago
Read 2 more answers
Two cars A and B leave an intersection at the same time. Car A travels west at an average speed of x miles per hour and car B tr
drek231 [11]

Answer:

Here is the C++ program:

#include <iostream>  // to use input output functions

#include <cmath>  // to use math functions like sqrt()

#include <iomanip>  //to use setprecision method

using namespace std;   //to access objects like cin cout

int main ()  {  //start of main function

  double speedA;  //double type variable to store average speed of car A

  double speedB;  //double type variable to store average speed of car B

  int hour;  //int type variable to hold hour part of elapsed time

  int minutes;  //int type variable to hold minutes part of elapsed time

  double shortDistance;  // double type variable to store the result of shortest distance between car A and B

  double distanceA;  //stores the distance of carA

  double distanceB;  //stores the distance of carB

  double mins,hours;   //used to convert the elapsed time

cout << "Enter average speed of car A: " << endl;  //prompt user to enter the average speed of car A

cin >> speedA;   //reads the input value of average speed of car A from user

cout << "Enter average speed of car B: " << endl ;  //prompt user to enter the average speed of car B

cin >> speedB;   //reads the input value of average speed of car A from user

cout << "Enter elapsed time (in hours and minutes, separated by a space): " << endl;  //prompts user to enter elapsed time

cin>> hour >> minutes;    //reads elapsed time in hours and minutes

  mins = hour * 60;  //computes the minutes using value of hour

  hours = (minutes+mins)/60;     //computes hours using minutes and mins

distanceA = speedA * (hours);  // computes distance of car A

distanceB = speedB * (hours);   //computes distance of car B

   shortDistance =sqrt((distanceA * distanceA) + (distanceB * distanceB));   //computes shortest distance using formula √[(distanceA)² + (distanceB)²)]

cout << "The (shortest) distance between the cars is: "<<fixed<<setprecision(2)<<shortDistance;

//display the resultant value of shortDistance up to 2 decimal places

Explanation:

I will explain the program with an examples:

Let us suppose that the average speeds of cars are:

speedA = 70

speedB = 55

Elapsed time in hours and minutes:

hour = 2

minutes = 30

After taking these input values the program control moves to the statement:

mins = hour * 60;  

This becomes

mins = 2 * 60

mins = 120

Next

hours = (minutes+mins)/60;

hours = (30 + 120) / 60

         = 150/60

hours = 2.5

Now the next two statements compute distance of the cars:

distanceA = speedA * (hours);  

this becomes

distanceA = 70 * (2.5)

distanceA = 175

distanceB = speedB * (hours);

distanceB = 55 * (2.5)

distanceB = 137.5

Next the shortest distance between car A and car B is computed:

shortDistance = sqrt((distanceA * distanceA) + (distanceB * distanceB));

shortDistance = sqrt((175 * 175) + (137.5 * 137.5))

                        = sqrt(30625 + 18906.25)

                        = sqrt(49531.25)

                        =  222.556173

shortDistance =  222.56

 

Hence the output is:

The (shortest) distance between the cars is: 222.56        

3 0
3 years ago
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