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Tema [17]
3 years ago
5

The perimeter of a rectangular parking lot is 296 m if the width of the parking lot is 65 m , what is its length

Mathematics
2 answers:
vampirchik [111]3 years ago
7 0

Answer:

perimeter(p)=2(l+b)

2(l+b)=296

where b = 65

2(l+65)=296

2l+130=296

2l=296_130

2l=166

l=166÷2

l= 83

Sophie [7]3 years ago
4 0

Answer:

166

Step-by-step explanation:

So the width is 65, so two sides are each 65m long. So multiply 65*2 which is 130. this means that the other two sides need to equal 130 when added, so divide 130/2 which is 65

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Length: 2w + 59

width: w

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w² - 4w + 3481 = 3721

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w = [-(b) +/- \sqrt{(b)^{2}  - 4(a)(c) }]/2(a)

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w = 1 + 2√61  ≈ 16.62

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Answer: width = 16.62 in, length = 92.24 in

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