The perimeter of a rectangular parking lot is 296 m if the width of the parking lot is 65 m , what is its length
2 answers:
Answer:
perimeter(p)=2(l+b)
2(l+b)=296
where b = 65
2(l+65)=296
2l+130=296
2l=296_130
2l=166
l=166÷2
l= 83
Answer:
166
Step-by-step explanation:
So the width is 65, so two sides are each 65m long. So multiply 65*2 which is 130. this means that the other two sides need to equal 130 when added, so divide 130/2 which is 65
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