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3 years ago

14

If s stadium pays $11,000 for labor and $7,000 for parking, what would the stadium's parking revenue have to be if the stadium i

s hoping parking labor for 6% of parking revenue?

1 answer:

Over [174]3 years ago

7 0

Could you restate the question it’s quite confusing

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If a cube has a side length of 4 1/2 cm, what is one way to write the volume of the cube?

lapo4ka [179]

Answer:

4.5^3 because we know v=lwh. since its a cube l, w, h will all equal 4.5

8 0

4 years ago

Sparky had room for 16 rows in his garden. He planted 3 rows of tomatoes for every 5 rows of onions. How many rows of onions did

tia_tia [17]

He would of had 15 bc he planted 3

5 0

4 years ago

Read 2 more answers

X is a normally distributed random variable with mean 62 and standard deviation 18.

maria [59]

Answer:

0.683

Step-by-step explanation:

If you have a calculator with statistical functions, this work is especially straightforward.

On the calculator, type in

normcdf(44,80,62, 18)

The calculator returns the result (probability) 0.683

4 0

3 years ago

Oliva works 4 hours each week more than lily

Fynjy0 [20]

Answer:

12 hours

Step-by-step explanation:

First it’s every 2 weeks so divide by 2 to find 1 week and get 16 hours a week then subtract 4 hours cause olivia works 4 more per week and u get 12 hours so Lily works 12 hours a week ;)

sorry if wrong have a good day/night

may i please have a branllest

7 0

3 years ago

Solve the equation. StartFraction dx Over dt EndFraction equals StartFraction 1 Over x e Superscript t plus 7 x EndFraction An i

MAVERICK [17]

Answer:

$\frac{1}{49}(7x-1)e^{7x}+e^{-t}=C$

Step-by-step explanation:

We are given that

$\frac{dx}{dt}=\frac{1}{xe^{t+7x}}$

We have to find the implicit function

Using separation variable method

$\frac{dx}{dt}=\frac{1}{xe^t\cdot e^{7x}}$

By using property $x^a\cdot x^y=x^{a+y}$

$xe^{7x}dx=e^{-t}dt$

By using property $\frac{1}{x^a}=x^{-a}$

Taking integration on both sides

$\int xe^{7x}dx=\int e^{-t}dt$

Parts integration method

$\int u\cdot v dx=u\int vdx-\int (\frac{du}{dx}\int vdx)dx$

By parts integration method

$x\int e^{7x}dx-\int (\frac{dx}{dx}\int e^{7x}dx)dx=-e^{-t}+C$

Using formula $\int e^{ax} dx=\frac{e^{ax}}{a}+C$

$\frac{xe^{7x}}{7}-\frac{1}{7}\int e^{7x}dx=-e^{-t}+C$

$\frac{xe^{7x}}{7}-\frac{1}{49}e^{7x}+e^{-t}=C$

$\frac{1}{49}(7x-1)e^{7x}+e^{-t}=C$

We are given that

$F(x,t)=C$

$F(x,t)=\frac{1}{49}(7x-1)e^{7x}+e^{-t}=C$

8 0

3 years ago