11+10=?????????????????????
3 is n and that is the answer
First year: the depreciation is (35/100) x 20000 = £7000; now the value of the car is £20000 - £7000 = £13000;
Second year: the depreciation is (35/100) x 13000 = £4550; the current value of the car is £13000 - £4550 = £8450.
Answer:
6 times 3 times 4
18 times 4
= 72
Step-by-step explanation:
hope this helps good luck
Answer: -10x (5x^3 - 8x^2 - 3x - 9) is the factored solution.