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katovenus [111]
3 years ago
8

Plot the x- and y-intercepts to graph the equation. y=−12x−3 could you guys plot it on a graph? if so thank you whichever one is

right ill give brainliest .
Mathematics
1 answer:
tamaranim1 [39]3 years ago
3 0

Answer:

(-4, 0)  (8, 0)

Step-by-step explanation:

I did the K12 test.

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Two whole numbers A and B satisfy the following conditions. Find A and B.
baherus [9]
Answer: A = 16 and B = 28

Explanation:
16 + 28 = 44
16:28 = 4:7
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8 0
3 years ago
Could someone help me
vekshin1

Answer:

Step-by-step explanation:      Try to solve it urself by putting necessary formulas of algebra that are in your textbook. thankyou!!!!!

8 0
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Step-by-step explanation:

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6 0
3 years ago
And then what is the answer in slope intercept form?
Reika [66]
Y= -2(x)+7 I'm pretty sure....
6 0
3 years ago
If f(1) = 0, what are all the roots of the function f(x)=x^3+3x^2-x-3? Use the Remainder Theorem.
Sophie [7]
There's no if about it, 

f(x)=x^3+3x^2-x-3


has a zero f(1)=0 so x-1 is a factor.   That's the special case of the Remainder Theorem; since f(1)=0 we'll get a remainder of zero when we divide f(x) by x-1.

At this point we can just divide or we can try more little numbers in the function.  It doesn't take too long to discover f(-1)=0 too, so  x+1 is a factor too by the remainder theorem.  I can find the third zero as well; but let's say that's out of range for most folks.

So far we have 

x^3+3x^2-x-3 = (x-1)(x+1)(x-r)

where r is the zero we haven't guessed yet.  Again we could divide f(x) by (x-1)(x+1)=x^2-1 but just looking at the constant term we must have

-3 = -1 (1)(-r) = r

so

x^3+3x^2-x-3 = (x-1)(x+1)(x+3)

We check f(-3)=(-3)^3+3(-3)^2 -(-3)-3 = 0 \quad\checkmark

We usually talk about the zeros of a function and the roots of an equation; here we have a function f(x) whose zeros are

x=1, x=-1, x=-3

8 0
3 years ago
Read 2 more answers
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