2 2/3 cups is = 128 teaspoons and 3/16 is = 9 teaspoon. 128÷9=14.22.. so the answer would be 14
Answer:
1/216
Step-by-step explanation:
The ratio of volumes of similar shapes is the cube of the scale factor. The filled portion of the cone is similar to the entire cone.
<h3>Linear scale factor</h3>
If the filled height is 1/6 of the total height, the scale factor for linear dimensions is 1/6.
<h3>Volume scale factor</h3>
The scale factor for the volume is the cube of the scale factor for linear dimensions. it is ...
(1/6)³ = 1/216
The volume of the filled portion of the cup is 1/216 of the volume of the cup.
X5, x6, x7, x12.7. It seemed to have been going into a pattern but then stops at the 2680. The pattern would be x5, x6, x7, x8 if the number was 1,680...?
Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900
There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20
The price of an advance ticket was 20.
The price of a same-day ticket was 15.
Answer:
X=the smaller
y=the larger
The bigger of two numbers is four more than the smaller, then:
y=x+4
one more than twice the smaller is the same as the larger, then
1+2x=y
We have the following system of equations:
y=x+4
y=2x+1
We solve this system by equal values method:
x+4=2x+1
x-2x=1-4
-x=-3
x=3
We find the value of "y"now:
y=x+4
y=3+4
y=7
the values of x and y are:
x=3
y=7
Step-by-step explanation:
