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3 years ago

Find the mean of the data in the dot plot below.

Mathematics

2 answers:

Nataly [62]3 years ago

7 0

Answer:

5km

Step-by-step explanation:

Harlamova29_29 [7]3 years ago

6 0

Answer:

tt3tg

Step-by-step explanation:

42t2tiohy20htt

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Surface area<br> Please help!!<br> Math, surface area

alisha [4.7K]

Answer:Surface area is the sum of the areas of all faces (or surfaces) on a 3D shape. A cuboid has 6 rectangular faces. ... We can also label the length (l), width (w), and height (h) of the prism and use the formula, SA=2lw+2lh+2hw, to find the surface area.

https://youtu.be/sskf3tF2heU?t=8

4 0

3 years ago

The mean number of words per minute (WPM) typed by a speed typist is 149149 with a standard deviation of 1414 WPM. What is the p

Semmy [17]

Answer:

The probability is $P(\= X > x ) = 0.78814$

Step-by-step explanation:

From the question we are given that

The population mean is $\mu = 149$

The standard deviation is $\sigma = 14$

The random number $x = 147.81$

The sample size is $n = 88$

The probability that the sample mean would be greater than $P(\= X > x ) = P( \frac{ \= x - \mu }{\sigma_{\= x} } > \frac{ x - \mu }{\sigma_{\= x} } )$

Generally the z- score of this normal distribution is mathematically represented as

$Z = \frac{ \= x - \mu }{\sigma_{\= x} }$

Now

$\sigma_{\= x } = \frac{\sigma }{\sqrt{n} }$

substituting values

$\sigma_{\= x } = \frac{14 }{\sqrt{88} }$

$\sigma_{\= x } = 1.492$

Which implies that

$P(\= X > x ) = P( Z > \frac{ 147.81 - 149 }{ 1.492} )$

$P(\= X > x ) = P( Z > -0.80 )$

Now from the z-table the probability is found to be

$P(\= X > x ) = 0.78814$

5 0

3 years ago

A transformation of AKLM results in AK'L'M'.

zysi [14]

Translation, Dilation

5 0

3 years ago

6y-5=11 what is y PLEASE HELP

svlad2 [7]

$6y-5=11 \\ 6y=11 +5 \\ 6y=16 \\ y= \frac{16}{6} =\frac{8}{3}$

8 0

3 years ago

Read 2 more answers

If y = 6x - 4 which of the following sets represents possible inputs and outputs of the function represented as ordered pairs?

noname [10]

The only of these that is a proper set of ordered pairs for this equations is A) (0,-4) (1,2) (3,14)

In order to prove this, you need to put each ordered pair into the equation and prove that it is a true statement. Below are the examples of this for A.

(0, -4)

y = 6x - 4

-4 = 6(0) - 4

-4 = 0 - 4

-4 = -4 (TRUE)

(1, 2)

y = 6x - 4

2 = 6(1) - 4

2 = 6 - 4

2 = 2 (TRUE)

(3, 14)

y = 6x - 4

14 = 6(3) - 4

14 = 18 - 4

14 = 14 (TRUE)

Therefore, each of these ordered pairs works in the equation.

7 0

3 years ago