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Mariulka [41]
3 years ago
5

Whats the future value of $1,500 after 5 years uf the appropriate interest rste is 6%, compoubded semiannually

Mathematics
1 answer:
masha68 [24]3 years ago
8 0

Answer:

$2015.84

Step-by-step explanation:

To calculate the Future value (or accumulated value (AV)) for compounding interest you use the following formula

PV(1+\frac{i}{n})^{i*n}

Where PV is present value

i is the interest rate

n is the number of times compounding a period

p is the number of periods (years)

so we have 1500(1+\frac{.06}{2})^{5*2}

If you put this in your calculator you get $2015.84

if you have any questions lmk

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Can someone help me with this? Please this would mean so much.
Paha777 [63]

Answers:

x = angle MLN = 35 degrees

angle FLJ = 55 degrees

=================================================

Explanation:

This problem is fairly tricky if you're not sure what to look for. A slight clue is that they've marked a red point that strangely doesn't have a label on it. It's a fairly small point but it's definitely there if you look closely. While this point's location isn't exactly what we want, we're fairly close. Start at point L and draw a ray through the center point P. Ray LP will intersect the circle at point A, as shown in the diagram below.

From here, draw segments FA and MA. Now notice that inscribed angle LMF = 55 and inscribed angle FAL both subtend the same arc. The term "subtend" basically means "cut off". This arc that the inscribed angles subtend is minor arc FL. A minor arc is where you travel the shorter path around the circle, which indicates its measure is less than 180 degrees.

Since inscribed angles LMF and FAL subtend the same minor arc, this makes the inscribed angles to be congruent.

In short: angle FAL is 55 degrees

----------------------

Segment LA goes through the center P. Through Thales theorem, we know that inscribed angle LFA is 90 degrees. Consequently, we can determine that inscribed angle FLA is 90-55 = 35 degrees.

Segment JL is tangent to the circle, meaning that angle ALJ is 90 degrees. So angle FLJ is 90-35 = 55 degrees.

It's not a coincidence that angle FLJ, angle FAL, and angle LMF are the same measure.

----------------------

We found that angle FAL was 55 degrees. Applying Thales theorem again shows that angle MAF is 90 degrees. Therefore, angle LAM is 90-55 = 35 degrees.

Focus now on triangle LMA. This is also a right triangle (Thales Theorem). The upper acute angle we found was angle LAM = 35, so the lower acute angle is ALM = 55.

Then we can find angle MLN = (angle ALN) - (angle ALM) = 90 - 55 = 35

In short, angle MLN = 35 degrees

Similar to the previous section, it is not a coincidence that angles LFM, LAM and MLN are the same measure.

------------------------

As an alternative, since we know angle FLJ = 55, and angle FLM is 90 degrees, this means...

(angle FLJ)+(angle FLM) + (angle MLN) = 180

55 + 90 + angle MLN = 180

145 + angle MLN = 180

angle MLN = 180 - 145

angle MLN = 35 degrees

7 0
3 years ago
PLEASE HELP<br><br> A<br><br> B<br><br> C<br><br> OR<br><br> D
iVinArrow [24]

Answer:

36 cm

Step-by-step explanation:

P = 2l + 2w

Plug in

P = 2(14) + 2 (4)

P = 28 + 8

P = 36

5 0
4 years ago
Read 2 more answers
The scores on the LSAT are approximately normal with mean of 150.7 and standard deviation of 10.2. (Source: www.lsat.org.) Queen
faltersainse [42]

Answer:

a=150.7 -0.385*10.2=146.773

So the value of height that separates the bottom 35% of data from the top 65% (Or the 35 percentile) is 146.7.  

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Solution to the problem

Let X the random variable that represent the  scores on the LSAT of a population, and for this case we know the distribution for X is given by:

X \sim N(150.7,10.2)  

Where \mu=150.7 and \sigma=10.2

We want to find a value a, such that we satisfy this condition:

P(X>a)=0.65   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.35 of the area on the left and 0.65 of the area on the right it's z=-0.385. On this case P(Z<-0.385)=0.35 and P(Z>-0.385)=0.65

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

Z=-0.385

And if we solve for a we got

a=150.7 -0.385*10.2=146.773

So the value of height that separates the bottom 35% of data from the top 65% (Or the 35 percentile) is 146.7.  

5 0
3 years ago
Read 2 more answers
A timer is started and a few moments later a model airplane is launched from the ground. Its height (in feet) as a function of t
WITCHER [35]

The airplane reaches its maximum height of 81 feet in 12 seconds.

<h3>Behavior of curves</h3>

If y = x^{2}, it means that the second derivate is 2 which is positive, then there is a minimum turning point.

If y = - x^{2}, it means that the second derivative will be -2 which is negative, then there is a maximum turning point.

Analysis:

h(t) = -(t - 12)^{2} + 81

By expanding,

h(t) = -(t^{2} - 24t + 144) +81

h(t) = -t^{2} + 24t - 144 + 81

h(t) = -t^{2} + 24t - 63

at turning point d/dt(h(t)) = 0

d/dt (h(t)) = -2t +24

-2t +24 = 0

if we differentiate again, second derivative is -2 which is negative, so it is a maximum point.

2t = 24

t  = 12 seconds

h(t) at t = 12

h(t) = -(12)^{2} + 24(12) - 63 = 81 feet

In conclusion, the maximum height of the airplane after 12 seconds is 81 feet.

Learn more about minimum and maximum points: brainly.com/question/14993153

#SPJ1

7 0
2 years ago
The Lcm of 4,9 what is that
Alexxandr [17]

Answer:

36

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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