Answer:
See below
Step-by-step explanation:
3x-429 + x/4 = 130 shows x = 172
QSN = 3x -429 = 87 degrees
HSX = 87 degrees
HSQ = 180 -87 = 93 degrees
XSN = x/4 = 43
PSN = 93 - 43 = 50
Answer:
yes ikr
Step-by-step explanation:
yes ikr
yes ikr
yes ikr
yes ikr
yes ikr
yes ikr
yes ikr
yes ikr
yes ikr
Answer:
B. TRUE.
(3, 2) is the intersection point of the graphs of
x + y = 5 and x - y = 1.
Step-by-step explanation:
Option B is TRUE because intersection point should satisfy both the equation
and in option be it comes true.
i.e x = 3 and y = 2 we have
3 + 2 = 5 and 3 - 2 = 1
5 = 5 and 1 = 1
Hence TRUE
A.
(3, 2) is the intersection point of the graphs of
3x + 2y = 5 and 3x - 2y = 1.
i.e x = 3 and y = 2 we have
3×3 + 2×2 = 5 and 3×3 - 2×2 = 1
13 ≠ 5 and 5 ≠ 1
Hence FALSE
C.
(5, 1) is the intersection point of the graphs of
3x + 2y = 5 and 3x - 2y = 1.
i.e x = 5 and y = 1 we have
3×5 + 2×3 = 5 and 3×5 - 2×3 = 1
21 ≠ 5 and 9 ≠ 1
Hence FALSE
D.
(5, 1) is the intersection point of the graphs of
x + y = 5 and x - y = 1.
i.e x = 5 and y = 1 we have
5 + 1 = 5 and 5 - 1 = 1
6 ≠ 5 and 4 ≠ 1
Hence FALSE
Answer:
y = ¹⁴/₄.x
Step-by-step explanation:
First of, if the bisector is perpendicular to the line segment, then we can find the gradient of the bisector (
) using the rule/principle:
Let:
m = gradient of the line segment
Then:
= 
We can find m since we have two points that fall on the line segment, (5, -9) and (-9, -5):
Δy/Δx
We can now find :
The equation of a line can be found using:
y - y₁ = m(x - x₁)
We have the gradient of the perpendicular bisector, the only other thing we need to identify the equation of the bisector is coordinates of a point that fall on the line;
We know the line will pass through the point exactly midway between (5, -9) and (-9, -5) since it is a bisector;
This can be found by:
We have a point on the line and the gradient so we can now find the equation:
