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baherus [9]
2 years ago
11

Need help with ratios quick plss

Mathematics
1 answer:
dalvyx [7]2 years ago
3 0
X/3=y this is what I got hopes this helps
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Is what I did a correct step?<br>If so, what is the next step?<br>​
qaws [65]
Next step would be 5x10x5
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3 years ago
What are the exact solutions of x^2 − 3x − 7 = 0?
bulgar [2K]

<u>Given</u>:

The given equation is x^{2} -3x-7=0

We need to determine the exact solutions of the equation.

<u>Exact solution:</u>

The exact solution of the equation can be determined by solving the equation using quadratic formula,

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

From the equation the values are a = 1, b = -3 and c = -7

Thus, substituting these values in the equation, we get;

x=\frac{-(-3) \pm \sqrt{3^2-4(1)(-7)}}{2(1)}

x=\frac{3 \pm \sqrt{9+28}}{2}

x=\frac{3 \pm \sqrt{37}}{2}

Thus, the exact solutions of the given equation is x=\frac{3 \pm \sqrt{37}}{2}

Hence, Option A is the correct answer.

6 0
3 years ago
Candice bought 4 notebooks that each cost the same amount. She paid with a $20 bill and received $10.32 in change. Write an equa
ohaa [14]

Answer:

(20-10.32)÷4=x

Step-by-step explanation:

6 0
2 years ago
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How is a topic different from a theme?
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Hi!

A topic is just a general thing you discuss, with no true moral ending you take away from it. A theme, on the other hand, wants to communicate a life lesson.

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2 years ago
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14 friends go out for dinner and the bill for food and drink comes to £130. The friends decided to add a 5% tip on the top of th
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The amount each friend does pay is £9.75

<h3>How to calculate the pay of each friend using fractions and arithmetic operations?</h3>

We are going to find 5% of the total amount paid and divide it by the numbers of all the friends to determine the amount paid by each one of them.

From the given information:

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  • Total amount paid = £130 + £6.5 = £136.5

Therefore, the cost of each friend is = \dfrac{136.5}{14}

The cost of each friend = £9.75


Learn more about fractions here:

brainly.com/question/78672

#SPJ1

4 0
1 year ago
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