Question

Matthew participates in a study that is looking at how confident students at SUNY Albany are. The mean score on the scale is 50. The distribution has a standard deviation of 10 and is normally distributed. Matthew scores a 65. What percentage of people could be expected to score the same as Matthew or higher on this scale

Answer 1

Answer:

The percentage of people that could be expected to score the same as Matthew or higher on this scale is:

= 93.3%.

Step-by-step explanation:

a) Data and Calculations:

Mean score on the scale, μ = 50

Distribution's standard deviation, σ = 10

Matthew scores, x = 65

Calculating the Z-score:

Z-score = (x – μ) / σ

= (65-50)/10

= 1.5

The probability based on a Z-score of 1.5 is 0.93319

Therefore, the percentage of people that could be expected to score the same as Matthew or higher on this scale is 93.3%.