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KATRIN_1 [288]
3 years ago
6

Which graph represents a function with direct variation?​

Mathematics
1 answer:
Nady [450]3 years ago
5 0
I’m pretty sure it’s the middle one .. because x and y currency throughout
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An electrician charges $322 for 7 hours of work. How much does the electrician charge for one hour?
In-s [12.5K]

Answer:

About 46 dollars an hour

Step-by-step explanation:

322/7 = 46

3 0
3 years ago
Can yall help its due in 30 minutes
MissTica

Answer:

$462.50

Step-by-step explanation:

:))

4 0
3 years ago
The spiders and ants in Aunt Mellys attic have a total of 152 legs and 22 heads. Spiders have 8 legs and ants have 6 legs. How m
Scorpion4ik [409]

Answer:

10 spiders and 12 ants

Step-by-step explanation:

You need to create two equations

s = # of spiders

a = # of ants

s + a = 22 heads

since each spider and ant has one head

8s + 6a = 152 legs

since every spider has 8 legs and every ant has 6

s + a = 22 can be turned into s = 22 - a

now use substitution

8(22 - a) + 6a = 152

176 - 8a + 6a = 152

176 - 2a = 152

24 = 2a

a = 12

now that you have the number of ants you can solve for the number of spiders

s + a = 22

s + 12 = 22

s = 10

6 0
2 years ago
Someone help please
Alla [95]

Answer:  Choice A

\tan(\alpha)*\cot^2(\alpha)\\\\

============================================================

Explanation:

Recall that \tan(x) = \frac{\sin(x)}{\cos(x)} and \cot(x) = \frac{\cos(x)}{\sin(x)}. The connection between tangent and cotangent is simply involving the reciprocal

From this, we can say,

\tan(\alpha)*\cot^2(\alpha)\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\left(\frac{\cos(\alpha)}{\sin(\alpha)}\right)^2\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\frac{\cos^2(\alpha)}{\sin^2(\alpha)}\\\\\\\frac{\sin(\alpha)*\cos^2(\alpha)}{\cos(\alpha)*\sin^2(\alpha)}\\\\\\\frac{\cos^2(\alpha)}{\cos(\alpha)*\sin(\alpha)}\\\\\\\frac{\cos(\alpha)}{\sin(\alpha)}\\\\

In the second to last step, a pair of sine terms cancel. In the last step, a pair of cosine terms cancel.

All of this shows why \tan(\alpha)*\cot^2(\alpha)\\\\ is identical to \frac{\cos(\alpha)}{\sin(\alpha)}\\\\

Therefore, \tan(\alpha)*\cot^2(\alpha)=\frac{\cos(\alpha)}{\sin(\alpha)}\\\\ is an identity. In mathematics, an identity is when both sides are the same thing for any allowed input in the domain.

You can visually confirm that \tan(\alpha)*\cot^2(\alpha)\\\\ is the same as \frac{\cos(\alpha)}{\sin(\alpha)}\\\\ by graphing each function (use x instead of alpha). You should note that both curves use the exact same set of points to form them. In other words, one curve is perfectly on top of the other. I recommend making the curves different colors so you can distinguish them a bit better.

6 0
2 years ago
Solve the following system of equations using substitution.
ollegr [7]

To solve system of equations by substitution, we are going to use the first equation to substitute into the second equation wherever you see y.

5x - 4y = -3

5x - 4(3x-5) = -3

5x -12x+20=-3

               -20     -20  

_______________

5x-12x=-23

-7x=-23

___    ____

 -7       -7

x=3.29 (rounded)

Next, substitute x = 3.29 into the first equation, or to any equation you'd like, to find y.

y = 3x-5

y = 3(3.29)-5

y = 9.87-5

y = 4.87

So, your final answer would be (3.29, 4.87).

7 0
3 years ago
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