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3 years ago

Whole note minus 1 half notes minus 2 quarter notes

Mathematics

2 answers:

Lapatulllka [165]3 years ago

8 0

1 - 1/2 - 2/4 = 0
A whole minus a half equals half minus another half (2/4) equals 0

Lilit [14]3 years ago

8 0

Hey there! :)

Assuming that we're speaking about musical notes, then we know that a whole note = 4 beats

So, we know that :

** whole note = 4 beats **

** half note = 2 beats **

**quarter note = 1 beat **

So, we are given the equation :

whole note - 1 half note - 2 quarter notes.

Plug in what we know.

(4) - (2) - (1) - (1)

Simplify.

2 - 1 - 1

1 - 1

So, our answer is 0 beats!

~hope this helped~

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3 years ago

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3 years ago

Read 2 more answers

Can u help solve these questions please

Tasya [4]

Answer:

Step-by-step explanation:

$\sqrt[4]{(16a^4)^5}=(16a^4)^{\frac{5}{4}}$ [Since, $\sqrt[n]{x}=x^{\frac{1}{n}}$ ]

$=(16)^{\frac{5}{4}}(a^4)^{\frac{5}{4}}$

$=(2^4)^{\frac{5}{4}}(a^4)^{\frac{5}{4} }$

$=(2^{4\times \frac{5}{4}})(a^{4\times \frac{5}{4}})$

$=2^5a^5$

$\sqrt[5]{(b^{\frac{1}{4}})^6}=\sqrt[5]{b^{\frac{6}{4}}}$

$=\sqrt[5]{b^{\frac{3}{2}}}$

$=(b^{\frac{3}{2}})^{\frac{1}{5} }$

$=b^{\frac{3}{10}}$

$\sqrt[3]{\frac{c^{15}}{c^9}}=\sqrt[3]{c^{15-9}}$

$=(c^6)^{\frac{1}{3}}$

$=c^{6\times \frac{1}{3} }$

= c²

$\sqrt[4]{16d^6\times 16d^{-5}}=\sqrt[4]{(2)^4(d^{6-5})(2)^4}$

$=\sqrt[4]{2^{(4+4)}d}$

$=\sqrt[4]{(2^8)d}$

$=2^{\frac{8}{4}}d^{\frac{1}{4}}$

$=2^2d^{\frac{1}{4}}$

$=4d^{\frac{1}{4}}$

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3 years ago

2x^2 + 3x - 47 = 0 Resolve essa conta ai pra mim faz favor :)

erma4kov [3.2K]

Answer:

x =4.155, x=− 5.655

x= - $\frac{3-\sqrt{385} }{4}$ , - $\frac{3+\sqrt{385} }{4}$

Step-by-step explanation:

2 $x^{2}$ + 3x - 47 = 0

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x =4.155, x=− 5.655

4 0

2 years ago