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3 years ago

Helppppppp what do I put, I need this by 10:00

Mathematics

1 answer:

Valentin [98]3 years ago

5 0

Answer:

As time increases the speed of the train decreases.

I think it is a decrease function.

Step-by-step explanation:

Hope this helps!!

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What is the y-value of the vertex of the function f(x)=-(x+3)(x-14)?

SIZIF [17.4K]

If we expand the product, we have

$f(x)=-(x+3)(x-14)=-x^2+11x+42$

The x-coordinate of the vertex is given by

$V_x=-\dfrac{b}{2a}=-\dfrac{11}{-2}=\dfrac{11}{2}$

Plug this value in the equation to find the correspondant y-value:

$f\left(\dfrac{11}{2}\right)=-\left(\dfrac{11}{2}\right)^2+11\left(\dfrac{11}{2}\right)+42=-\dfrac{121}{4}+\dfrac{121}{2}+42$

5 0

4 years ago

Solve by using the given theorems of logarithms. log 5 + log 2 =

madam [21]

Answer:

Step-by-step explanation:

Using the rule of logarithms

log x + log y ⇔ log(xy)

$log_{b}$ b = 1

Hence

log 5 + log 2 = log(5 × 2) = log 10 = 1

5 0

3 years ago

Ron went to the store with $100.00 he bought 2 belts for $14.00 each, he bought 3 shirts for $15.00 each, and he bought a pair o

nlexa [21]

Answer:

Step-by-step explanation:

100-14-15-25 is 46

5 0

3 years ago

if you have one and a half loaf of bread and you have twelve people. which size of bread will each get

Natalija [7]

Answer:

1/8 of a loaf

Step-by-step explanation:

Divide the 1.5 loafs by 12 people

7 0

3 years ago

Which equation does this image represent?

nirvana33 [79]

Given:

Image of the ellipse

To find:

The equation of the image

Solution:

The given image is a ellipse.

Center of the ellipse = (0, 0)

x-axis points are (-3, 0) and (3, 0).

y-axis points are (2, 0) and (-2, 0).

Standard form of equation of ellipse:

$$\frac{(x-h)^{2}}{a^{2}}+\frac{(y-k)^{2}}{b^{2}}=1$

where (h, k) is the center = (0,0)

a is the point on x-axis where y = 0. Hence a = 3.

b is the point on y-axis where x = 0. Hence b = 2.

Substitute this in the standard form of ellipse.

$$\frac{(x-0)^{2}}{3^{2}}+\frac{(y-0)^{2}}{2^{2}}=1$

$$\frac{x^{2}}{9}+\frac{y^{2}}{4}=1$

To make the denominator same multiply 1st term by $\frac{4}{4}$ and 2nd term by $\frac{9}{9}$ .

$$\frac{4x^{2}}{4\times9}+\frac{9y^{2}}{9\times4}=1$

$$\frac{4x^{2}}{36}+\frac{9y^{2}}{36}=1$

$$\frac{4x^{2}+9y^{2}}{36}=1$

Multiply by 36 on both sides

$$\frac{4x^{2}+9y^{2}}{36}\times 36=1\times 36$

$${4x^{2}+9y^{2}}={36}$

The equation of the image is $${4x^{2}+9y^{2}}={36}$ .

8 0

4 years ago

Helppppppp what do I put, I need this by 10:00​

Helppppppp what do I put, I need this by 10:00