All categories

2 years ago

Need help with this math please

Mathematics

1 answer:

Nana76 [90]2 years ago

3 0

Here you go. Have fun

You might be interested in

Find the following when a = -1, b = 2, c = -1/4<br> (4b - 3)/(2a) -1

Katena32 [7]

We substitute the given into the equation
given: a=-1, b=2, c= $\frac{-1}{4}$
=( $\frac{4b-3}{2a}$ -1
= $\frac{4(2)-3}{2(-1)}$ -1
= $\frac{8-3}{-2}$ -1
= $\frac{5}{-2}$ -1
to continue, we can either find a common denominator or change the fraction to decimal.
Fraction to Decimal:
$\frac{5}{-2}$ =-2.5
Equation=-2.5-1=-3.5
OR Common Denominator:
= $\frac{5}{-2}$ $\frac{-1}{1}$ × $\frac{-2}{-2}$ (denominator should be -2=common)
= $\frac{5}{-2}$ + $\frac{2}{-2}$
= $\frac{7}{-2}$
which also = to -3.5

3 0

2 years ago

The table represents some points on the graph of a linear function.

Sunny_sXe [5.5K]

Answer:

B. $-\frac{9}{2}$

Step-by-step explanation:

Rate of change of y with respect to x, can be calculated using any two of the pairs of values of the table, say, (-2, 12) and (0, 3).

Rate of change = $\frac{y_2 - y_1}{x_2 - x_1}$

Let,

$(-2, 12) = (x_1, y_1)$

$(0, 3) = (x_2, y_2)$

Plug in the values

Rate of change = $\frac{3 - 12}{0 - (-2)} = \frac{-9}{2} = -\frac{9}{2}$

7 0

2 years ago

A Class 4 truck weighs between 14,000 and 16,000 pounds.

Nady [450]

Answer:

Class 4: This class of truck has a GVWR of 14,001–16,000 pounds or 6,351–7,257 kilograms. Class 5: This class of truck has a GVWR of 16,001–19,500 pounds or 7,258–8,845 kilograms.

Step-by-step explanation:

6 0

2 years ago

Grehyesjeyehevshsh. *Cries in no knowledge*

PilotLPTM [1.2K]

Answer:

GIRL ITS M!!!!!!

Step-by-step explanation:

its the furthest to the right on the number line

6 0

2 years ago

Item: c = p(1 + ). What is the final cost of a $40 item after an 8% tax is applied?

Snowcat [4.5K]

40(0.08) = 3.2

3.2+40

Answer: 43.20

5 0

2 years ago