Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]
the area of each trapezoid is (v(t1)+v(t2))/2 times width
for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8
2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24
3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75
4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7
add them all up
0.8+2.24+1.75+0.7=5.49
5.49
t=time
v(t)=speed
so the area under the curve is distance
covered 5.49 meters
Answer:
c. 5
Step-by-step explanation:
678 rounds to 700 and 218 rounds to 200. 700-200=500
280 mg = 70 Ml
280/70 = 4
50 mL x 4 = 200 mg
200 mg
Answer:
The answer is "
"
Step-by-step explanation:






Eight phenotypes were present.
Df is provided also by a number of phenotypes -1 The degree of freedom

For p-value 0,9, Chi-square is 2.83;
The p-value of 0.75 is 4.5. Chi-square
Chi-sqaure value is observed at 2.965.
That means 0.90>p-value>0.75.
The cube has 6 this same faces.
Therefore the surface area is equal 6 · 7cm² = 42cm²