The length of a rectangle is 6 centimeters and it's area is (6x 18) square centimeters. Write the expression for the width

In an investigation of pregnancy-induced hypertension, one group of women with this disorder was treated with low-dose aspirin,

AleksandrR [38]

Answer:

Step-by-step explanation:

Given that in an investigation of pregnancy-induced hypertension, one group of women with this disorder was treated with low-dose aspirin, and a second group was given a placebo. A sample consisting of 50 women who received aspirin has mean arterial blood pressure 120mmHg and standard deviation 10mmHg; a sample of 42 women who were given the placebo has mean blood pressure 115mmHg and standard deviation 12mmHg.

Population variances are equal

$H_0: \bar x = \bar y\\H_a: \bar x \neq \bar y$

(two tailed test at 5% significance level)

Here x denotes group I and Y group II

N Mean StDev SE Mean

Sample 1 50 120 10 1.4142

Sample 2 42 115 12 1.8516

Pooled std deviation = 10.9565

df=80

Mean difference= 5

Test statistic t = mean diff/std error = $\frac{5}{2.3299}$ =2.1803

p value = 0.0318

since p <0.05 we reject H0

b) We find p >0.01 hence at 1% significance level we accept H0

This implies that 99% confidence interval contains mean difference =0

4 0

4 years ago

If the probability of success during a single event on a geometric experiment is 0.34 what is the probability of success of the

sasho [114]

Answer:

5th Event, 6.5% (APEX)

Step-by-step explanation:

8 0

3 years ago

The manager at a movie theater keeps track of the number of evening tickets and matinee tickets sold each day and the total mone

Alex Ar [27]

Let the number of Matinee tickets be x
Let the number of evening tickets be y
Number of sold tickets = 63, this means that: x+y = 63 ......> equation I
Price of matinee ticket = 10 and price of evening tickets = 14
Total money collected = 742, this means that 10x + 14y = 742 .....> equation II

From equation I: x = 63 - y .........> equation III

Substitute by equation III in equation II:
10(63-y) + 14y = 742
630 - 10y + 14y = 742
4y = 742 - 630 = 112
y = 112/4 = 28
Substitute by the value of y is equation III:
x = 63-28 = 35

Based on the above calculations:
number of matinee tickets = x = 35 tickets
number of evening tickets = y = 28 tickets

4 0

3 years ago

Solve by using the quadratic form<br> 5r^2-8r+20=0

nevsk [136]

Answer:

Step-by-step explanation:

3 0

3 years ago

7) Suppose that the amount of time it takes to process insurance claims is normally distributed with a mean of 12 weeks and a va

Alina [70]

This question is incomplete, the complete question is;

Suppose that the amount of time it takes to process insurance claims is normally distributed with a mean of 12 weeks and a variance of 9 weeks. What is the probability that the next claim will be processed within; a) 10 weeks, b) 11 weeks, c) 12 weeks.

Answer:

a) the probability that the next claim will be processed within 10 weeks is 25.14%

b) the probability that the next claim will be processed within 11 weeks is 37.07%

c) the probability that the next claim will be processed within 12 weeks is 50.00%

Step-by-step explanation:

Given the data in the question;

mean 12 weeks

Variance = 9 weeks

Standard deviation SD = √Variance = √ 9 = 3 weeks.

Since, the amount of time it takes to process insurance claims is normally distributed.

z = ( x - mean ) / SD

where x is weeks of next claim.

a) 10 weeks

z = ( x - mean ) / SD

we substitute

z = ( 10 - 12 ) / 3

z = -2/3

z = -0.67

{ from standard normal distribution table }

value of z is 0.2514

Therefore, the probability that the next claim will be processed within 10 weeks is 25.14%

b) 11 weeks

z = ( x - mean ) / SD

we substitute

z = ( 11 - 12 ) / 3

z = -1/3

z = -0.33

{ from standard normal distribution table }

value of z is 0.3707

Therefore, the probability that the next claim will be processed within 11 weeks is 37.07%

c) 12 weeks

z = ( x - mean ) / SD

we substitute

z = ( 12 - 12 ) / 3

z = 0/3

z = 0.00

{ from standard normal distribution table }

value of z is 0.5000

Therefore, the probability that the next claim will be processed within 12 weeks is 50.00%

7 0

3 years ago