3 years ago

I need help for this question.

Mathematics

1 answer:

Akimi4 [234]3 years ago

6 0

Answer:

the water rises 50ft per minute so for 60min you have to multiply 60 x 50 which will be 3000ft in 60mins

Step-by-step explanation:

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How are fractions and ratios the same? How are they different?

natta225 [31]

Answer:

Step-by-step explanation:

Ratios depend on the numbers that are being compared. When you are describing a part of a whole, a fraction is appropriate. When you are comparing two numbers, a ratio is appropriate.

Basically you can write ratio as fraction

Ex-4:2, 4/2

See what I mean?

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4 years ago

Which is the graph of a function and it’s inverse? THE ANSWER IS NOT D. Please help I’ll mark brainliest!

nika2105 [10]

I’m pretty sure it’s B!

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3 years ago

On May 23, 2013, Gallup reported that of the 1,005 people surveyed, 76% of U.S. workers believe that they will continue working

kumpel [21]

Answer: 0.76

Step-by-step explanation:

We know that the sample proportion is the best estimate of the population proportion. (1)

Given : Gallup reported that of the 1,005 people surveyed, 76% of U.S. workers believe that they will continue working past retirement age.

Let p be the population proportion.

We have sample proportion: $\hat{p}=76\%=0.76$

Therefore, the estimated proportion of U.S. workers believe that they will continue working past retirement age from the sample = $\hat{p}=0.76$

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3 years ago

The brightness of a star is called its Absolute magnitude (M). The equation M = a + 5 - 5 log d is used to find the Absolute mag

agasfer [191]

Hello,

d=10^((5+0.009-0.45)/5) parsec
≈8,162064...parsec
≈1683546.565738...ua
≈2.5185498*10^17 m
≈26,62109273... light-years.

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3 years ago

Based on Pythagorean identities, which Equation is true?

Pavel [41]

The answer is cot² ∅ - csc² ∅ = -1

Referring to Pythagorean identities:
sin² ∅ + cos² ∅ = 1
1+cot² ∅ = csc² ∅
tan² ∅ + 1 = sec² ∅

1+cot² ∅ = csc² ∅
⇒ transposing 1 and csc² ∅ we will have now
cot² ∅ - csc² ∅ = -1

8 0

3 years ago

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I need help for this question.​

I need help for this question.