Answer:
If y(x-y)^2=x, then int1/(x-3y)dx is equal to (A) 1/3log{(x-y)^2+1} (B) 1/4log{(x-y)^2-1} (C) 1/2log{(x-y)^2-1} (D) 1/6 log{(x^2-y^2-1}
Step-by-step explanation:
The correct answer is 17 what i did was plug in 17 where ever you see x so x2 would be 17x2 an then plus the 5 gives u 39 3x 17x3=51 51+10=61 now add the totals 61 plus 39 gives u 100
For the 11 the first one is x = 4y and for the 2 one it will be x=−6−2y
Answer:
-4m-3
Step-by-step explanation:
-0.25 times 16 is the same thing as dividing 16 by -4. 16m divided by -4 is -4m
-0.25 times 12 is the same thing as dividing 12 by -4. 12 divided by -4 is -3
