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3 years ago

WORTH 100 POINTS NEED DONE ASAP WRONG ANSWERS WILL BE REPORTED THANK YOUUU

Mathematics

1 answer:

zysi [14]3 years ago

7 0

Answer:

1.x=√(15²-12²)=√81=9

2.x=√(6²+6²)=6√2

3.c=√(√19²-√7²)=√(19-7)=√12

Step-by-step explanation:

4.h=10

a=b=x

we have

by using Pythagoras law

h²=x²+x²

100=2x²

x²=50

x=√50=5√2

both legs =5√2

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Dmitry_Shevchenko [17]

Answer:

55 degrees

Step-by-step explanation:

angle adds up to 360. your equation would be 360 = 2(125) + 2(angleN)

7 0

3 years ago

Splve for x. -1.4x = 4(x + 2.18)

Georgia [21]

X=-218/135 Or x=1.61481

5 0

3 years ago

Read 2 more answers

Which phrase best describes the translation from the graph y = (x – 5)2 + 7 to the graph of y = (x + 1)2 – 2?

Andreas93 [3]

The parent. function shifted up by 6 units to produce x + 1 and to the left by 9 units

<h3>What is translation?</h3>

This is a way of changing the position of an object on an xy-plane.

Given the parent function expressed as y = (x – 5)^2 + 7

From the resulting image after translation, we can see that the parent. function shifted up by 6 units to produce x + 1 and to the left by 9 units

Learn more on translation here; brainly.com/question/12861087

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8 0

2 years ago

David's bowling score is 6 less than 2 times Aaron's score. The sum of their scores is 84. Find the score of each student. Use t

Y_Kistochka [10]

Answer:

Aaron's bowling score is 30

David's bowling score is 54

Step-by-step explanation:

The variable representing Aaron's score is = a

The variable representing David's bowling score = d

The sum of their scores is 84.

= a + d = 84...... Equation 1

David's bowling score is 6 less than 2 times Aaron's score.

d = 2a - 6

Substituting 2a - 6 for d in Equation 1

a + 2a - 6 = 84

3a - 6 = 84

3a = 84 + 6

3a = 90

a = 90/3

a = 30

Hence, Aaron's bowling score is 30

d = 2a - 6

d = 2(30) - 6

d = 60 - 6

d = 54

David's bowling score is 54

8 0

3 years ago

Determine whether the integral is convergent or divergent. ∫[infinity] 2 e^−1/x / x^2 dx : O Convergent O divergent If it is con

monitta

Let $f(x)=e^{-1/x}$ . Then $f'(x)=\frac1{x^2}e^{-1/x}>0$ for all $x\ge2$ , so $f$ is strictly increasing. As $x\to\infty$ , $e^{-1/x}\to e^0=1$ , so $f$ is bounded above by 1. This is to say,

$e^{-1/x}$

and the integral of $\frac1{x^2}$ converges over the same domain, so this integral must also converge by comparison.

We have, by setting $y=-\frac1x$ ,

$\displaystyle\int_2^\infty\frac{e^{-1/x}}{x^2}\,\mathrm dx=\int_{-1/2}^0e^y\,\mathrm dy=e^0-e^{-1/2}=1-\frac1{\sqrt e}$

8 0

3 years ago