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kicyunya [14]
3 years ago
5

What is the answer to 15-9:(-3)

Mathematics
2 answers:
Zolol [24]3 years ago
8 0

Answer:

good questiion

Step-by-step explanation:

Juliette [100K]3 years ago
4 0
The answer for your question is 42
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A football player completes 19 of his 25 passes during the season. What percent of his passes did the player complete? Use fract
d1i1m1o1n [39]
19/25 is the answer for this one.
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Matt gave 5 apples to his son and sold 8 times as many apples. If Matt had 1/2 of the apples left, how many did he have in the b
Gala2k [10]

Answer:

90

Step-by-step explanation:

8*5 = 40

40 + 5 = 45

1/2 x = 45

x = 90

4 0
3 years ago
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Can someone please help me extra points
Maslowich

Answer:

4) m: 1.25   b: 6         Equation: y= 1.25x + 6

5) m: 20      b: 10     Equation: y= 40x + 10

6) m: -2       b: 0       Equation: y= -2x + 0

7) m: 1/5      b: 1       Equation: y= 1/5x + 1

8) -8.7 = 1.3x + 0

I really hope this helps!

3 0
3 years ago
A tool used to measure small distances and lengths.
scoray [572]
Ruler


I have to write more so ignore this
6 0
3 years ago
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Find the zeros of the function f(x) = x2 + 5x + 6. A) y = 6 because the graph crosses the y-axis at 6. B) y = -0.25 because that
Fofino [41]

Answer:

D.)

Step-by-step explanation:

The zero's are referencing when y=0, note that when y=0 they are talking about the x-intercepts.  You can graph the function and see when the graph crosses the x-axis or solve for the x-values.  I will solve it via factoring and so:

f(x)=x^2+5x+6

Multiply the outer coefficients, in this case 1 and 6, and 1×6=6.  Now let's think about all the factors of 6 we have: 6×1 and 2×3.  Now is there a way that if we use any of these factors and add/subtract them they will return the middle term 5?  Actually we can say 6-1=5 and 2+3=5.  Let's try both.

First let's use 6 and -1 and so:

x^2+5x+6\\\\x^2+6x-x+6\\\\x(x+6)-1(x-6)

Notice how we have (x+6) and (x-6), these factors do not match so this is incorrect.

Now let's try 2 and 3 and so:

x^2+5x+6\\\\x^2+3x+2x+6\\\\x(x+3)+2(x+3)\\\\(x+2)(x+3)

Notice how the factors (x+3) matched up so this is a factor and so is (x+2), now to solve for the zero's let's make f(x)=0 and solve each factor separately:

Case 1:

f(x)=x+2\\\\0=x+2\\\\x=-2

Case 2:

f(x)=x+3\\\\0=x+3\\\\x=-3

So your zero's are when x=-2 and x=-3.

D.) x=-3 and x=-2 because the graph crosses the x-axis at -3 and -2.


~~~Brainliest Appreciated~~~

8 0
3 years ago
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