Change X and Z. X is first evening
Y is second
Z is third evening
A. you plug in to a calculator, which will give 1840.986 so you need to round up to 1840.99. if you truncate it to .98 then he won't reach 2000 in 3 years
b. for this one if you look at the equation given to find the principle it is principle = result (1+rate) ^ -time
if you re arrange this you get result=principle (1+rate)^time
so result = 1840.99(1.028)^5
= 2113.57
Answer:
<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>
Step-by-step explanation:
Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:
<h3>To find how many imaginary roots does the polynomial have :</h3>
- Since the degree of given polynomial is 4
- Therefore it must have four roots.
- Already given that the given polynomial has 1 positive real root and 1 negative real root .
- Every polynomial with degree greater than 1 has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>
Answer: 18
<u>Do Keep Change Flip (KCF)</u>
Keep: 9/2
Change: ÷ into ×
Flip: 1/4 into 4/1
Your new problem should be 9/2×4/1
<u>Multiply</u>
9/2×4/1=36/2
36/2=18
Final Answer: 18
Answer:
1/4
Step-by-step explanation:
5 orange + 5 mango = 10
P( mango ) = mango /total = 5/10 = 1/2
Replace
5 orange + 5 mango = 10
P(orange ) = orange /total = 5/10 = 1/2
P(mange, replace, orange) = 1/2 * 1/2 = 1/4
