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Simora [160]
3 years ago
6

Molly spent 1 hour and 30 minutes swimming 5 laps in the river. If it took her the same time to swim each lap, how long would it

take her to swim 7 laps?
Mathematics
1 answer:
-Dominant- [34]3 years ago
3 0

Answer:

126 minutes or 2 hours and 6 minutes

Step-by-step explanation:

Find how long it took her to swim one lap

1 hour and 30 minutes = 90 minutes

90/5 = 18

This means it took her 18 mins to swim each lap

18 · 7 = 126

It took her 126 minutes/2 hours and 6 minutes to swim 7 laps

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Step by step explanation

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3 years ago
4+ -1 2/3 please help
kogti [31]

The sum would end us as: 2.33333333

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Read 2 more answers
please help :) What is 7.7 x 10 to the 8 power written in standard form? A. 770,000,000 B. 77,000,000,000 C. 77,000,000 D. 7,700
Serjik [45]

Answer:

A. 770,000,000

Step-by-step explanation:

7.7x10^8 First step is to simplify

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7 0
3 years ago
Write the following polar equation in Cartesian coordinates:
maks197457 [2]
Remember that transformation between Cartesian and polar system are:
x=r*cos(α)
y=r*sin(α)
From this we can conclude that:
r=√(x^2 + y^2)

Using trigonometry transformations we can write:
r=sin(2α) = 2sin(α)cos(α)
Now we can multiply both sides with r^2:
r^3 = 2(r*sin(α))*(r*cos(α))

Now using some replacements we can write:
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5 0
3 years ago
Use the following steps to prove that log b(xy)- log bx+ log by.
borishaifa [10]

Answer with Step-by-step explanation:

a.x=b^p

y=b^q

Taking both sides log

log x=plog b

Using identity:logx^y=ylogx

p=\frac{logx}{log b}=log_b x

Using identity:log_x y=\frac{log y}{log x}

log y=qlog b

q=\frac{log y}{log b}=log_b y

b.xy=b^pb^q

We know that

x^a\cdot x^b=x^{a+b}

Using identity

xy=b^{p+q}

c.log_b(xy)=log_b(b^{p+q})

log_b(xy)=(p+q)log_b b

Substitute the values then we get

log_b(xy)=(log_b x+log_b y)

By using log_b b=1

Hence, log_b(xy)=log_b x+log_b y

3 0
3 years ago
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