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Sati [7]
4 years ago
8

three girls searched for geodes in the desert Corinne collected 11 1/8 pounds, Ellen collected 4 5/8 pounds, and Leonda collectr

d 3 3/4 pounds. How much more did Corinne collect than the other two girls combined?
Mathematics
2 answers:
lutik1710 [3]4 years ago
8 0
15/4 + 27/8 = 57/8 89/8 - 57/8 = 32/8 = 4
9966 [12]4 years ago
6 0
Corrine collected 11 1/8 geodes or 89/11 geodes.
Ellen collected 4 5/8 geodes or 27/8 geodes.
Leonda collected 3 3/4 geodes or 15/4 geodes.

Ellen and Leonda collected a total of 27/8 + 15/4 geodes.
They collected 27+30/8 = 57/8 geodes.

Corrine collected 89/11 - 57/8 more geodes.
She collected (89*8 - 57*11)/88 = 85/88 geodes more.
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A coin is tossed 600times with the frequencies as:
brilliants [131]

Answer:

  • see below

Step-by-step explanation:

Total number of trials =600.

Number of heads = 342.

Number of tails = 258

On tossing a coin,

let  \: E_1  \: and  \: E_2  \: be  \: the  \: events \:  of \:  getting  \: a  \: head

and of getting a tail respectively.

then,

1)  \: P \:  (getting \:  a  \: head) = \: P \:  (E_1)

\longrightarrow \:  \frac{number \: of \: heads \: coming \: up}{total \: number \: of \: trials}

\longrightarrow \:  \frac{342}{600}  =  \frac{57}{100}

\longrightarrow \: 0.57

\red{ \rule{150pt}{3pt}} \:

2) P (getting \: a\: tail) =P (E_2)

\longrightarrow \:  \frac{number \: of \: tails \: coming \: up}{total \: number \: of \: trials}

\longrightarrow \:  \frac{258}{600}  =  \frac{43}{100}

\longrightarrow \: 0.43

6 0
3 years ago
Please Please answer this correctly I have to finish this today as soon as possible
mr_godi [17]

Answer:

about 173⁰

Step-by-step explanation:

because it's very close to 180⁰ but isnt it, I'd say between 170 and 180

173 to be safe

3 0
3 years ago
Brian divided 64 ounces of fruit punch into 6 1/3 ounce servings.He has 2/3 ounce of punch left over.How many 6 1/3 ounce servin
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Brian made 10 servings
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How do u solve A/B + C/D = E
Flauer [41]
You cannot solve this, I don’t see how....
5 0
3 years ago
The senate in a certain state is compromised of 58 republicans, 39 democrats, and 3 independents. How many committees can be for
Nutka1998 [239]
Defining C(n,r) as the number of combinations (order does not count) to choose r objects from n, where C(n,r)=n!/(r!(n-r)!)
there are 
C(58,3) ways to choose 3 from 58 republicans, 
and
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So the committee has
(C(58,3)*(C(39,2)) variants, or
58!/(3!55!) * 39!/(2!37!)
=30856*741
=22864296

5 0
4 years ago
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