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ASHA 777 [7]
3 years ago
6

If a=mg-kv2/m,find,correct to the nearest whole number the value of v when a=2.8,m=12,g=9.8 and k=8/3

Mathematics
1 answer:
RUDIKE [14]3 years ago
6 0

Answer:

The value of v is ± 22.729.

Step-by-step explanation:

Let be a=m\cdot g -\frac{k\cdot v^{2}}{m}, the variable v is now cleared:

\frac{k\cdot v^{2}}{m}=m\cdot g -a

k\cdot v^{2} = m^{2}\cdot g- m\cdot a

v^{2} = \frac{m^{2}\cdot g - m\cdot a}{k}

v =\pm \sqrt{\frac{m^{2}\cdot g-m\cdot a}{k} }

If a = 2.8, m=12, g = 9.8 and k = \frac{8}{3}, the value of v is:

v=\pm \sqrt{\frac{(12)^{2}\cdot (9.8)-(12)\cdot (2.8)}{\frac{8}{3} } }

v \approx \pm 22.729

The value of v is ± 22.729.

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One endpoint of a line segment is (–6, 4), and the midpoint of the segment is (–2, 7). What are the coordinates of the other end
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Answer:

A. (2, 10)

Step-by-step explanation:

If there are two points (x1,y1) and (x2,y2) on a coordinates plane then

coordinates of the midpoint is given by (x1+x2)/2, (y1+y2)/2

__________________________________________________

Given

one endpoint is (–6, 4) and midpoint is (–2, 7)

let coordinates of other endpoint be (x,y)

now if one endpoint is (–6, 4) and other endpoint is (x,y)

then coordinates of midpoint is ((-6+x)/2 , (4+y)/2)

while the coordinates of midpoint given  is  (–2, 7)

thus (–2, 7) should be equal to ((-6+x)/2 , (4+y)/2)

-2 = (-6+x)/2             and   7 = (4+y)/2

=> -2*2 = -6+x                 => 7*2 = 4+y

=> -4 = -6+x                    => 14 = 4+y

=> -4+6 = x                     => 14-4 = y

=> x = 2                           => 10 = y

Thus, coordinates of the other endpoint is(2,10)

6 0
3 years ago
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3 years ago
What is the height of the wall that is 30 feet long and that required 2310 bricks to build
Diano4ka-milaya [45]
(2310)=7(30)H
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<span>11=H

I hope this helps!
</span>
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Answer:

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4 0
2 years ago
Read 2 more answers
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