Answer:
Suppose we have a random number A.
The multiplicative inverse of A is a number X such that:
A*X = 1
When we work with real numbers, X = 1/A
Then:
A*(1/A) = A/A = 1
This means that (1/A) is the multiplicative inverse of A.
Where we need to have A ≠ 0, because we can not divide by 0.
Now we want to find the multiplicative inverse of the numbers:
2: Here the inverse is (1/2) = 0.5
1/5: Here the inverse is (1/(1/5)) = (5/1) = 5
-4: Herre the inverse is (1/(-4)) = -(1/4) = -0.25
The answer is B on edgeunity
The curve given has asymptotes at x=0 and y=0. We wish to move it right 7 units so the asymptote becomes x=7 and down 5 so the asymptote is y=-5
To move a function down 5 units subtract 5 from it. To move it right we subtract 7 from the independent variable (from the x). The new function is y=(3/(x-7))-5
y= (3 over (x-7)) then minus 5
-32/40 + -35/40 = -32+-35/40
= -67/40
= -1.675
The answer would then be -1.675.
