Answer:
4 is 1
5 is 2
Step-by-step explanation:
hope this helps:P
To check for continuity at the edges of each piece, you need to consider the limit as approaches the edges. For example,
has two pieces, and , both of which are continuous by themselves on the provided intervals. In order for to be continuous everywhere, we need to have
By definition of , we have , and the limits are
The limits match, so is continuous.
For the others: Each of the individual pieces of are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.
Answer:
I had x to be 2
Step-by-step explanation:
a square has all it side to be equal
so 10x=6x+8
you will group like terms 10x-6x=8
4x=8 you divide both side by the coefficient of x which is four so X=2