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3 years ago

Pls help this question bamboozles me and I am now sitting here confused

Mathematics

1 answer:

UkoKoshka [18]3 years ago

4 0

Answer:

10+3pi

Step-by-step explanation:

The perimeter of of the shaded region is

AC+CT+marcSBT+SA

*Finding AC

The diagonals of a rectangle are equal is measurement. Since RB is a radius of the circle, then RB is 6. Since AC and RB are both diagonals of the rectangle, then AC is also 6.

*Finding CT

CT=RT-RC where RC is the width of the rectangle

Also RT is a radius so we have that

CT=6-RC

*Finding marcSBT

The circumference of a whole circle is 2pi*r.

We have a quarter of this with r=6.

1/4*2pi(6)

1/4*12pi

3pi

*Finding SA

SA=RS-AR

RS is a radius of the circle and AR is the length of the rectangle.

So we have that this can be rewritten as

SA=6-AR

Let's put these parts together:

6+6-RC+3pi+6-AR

Simplifying:

18-RC-AR+3pi

18-(RC+AR)+3pi

18-8+3pi (Remember length plus width equal 8)

10+3pi

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The following information was obtained from independent random samples taken of two populations. Assume normally distributed pop

Volgvan

Answer:

1. The 95% confidence interval for the difference between means is (-5.34, 11.34).

2. The standard error of (x-bar1)-(x-bar2) is 4.

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{9.2195^2}{10}+\dfrac{9.4868^2}{12}}\\\\\\s_{M_d}=\sqrt{8.5+7.5}=\sqrt{16}=4$

Step-by-step explanation:

We have to calculate a 95% confidence interval for the difference between means.

The sample 1, of size n1=10 has a mean of 45 and a standard deviation of √85=9.2195.

The sample 2, of size n2=12 has a mean of 42 and a standard deviation of √90=9.4868.

The difference between sample means is Md=3.

$M_d=M_1-M_2=45-42=3$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{9.2195^2}{10}+\dfrac{9.4868^2}{12}}\\\\\\s_{M_d}=\sqrt{8.5+7.5}=\sqrt{16}=4$

The critical t-value for a 95% confidence interval is t=2.086.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_{M_d}=2.086 \cdot 4=8.34$

Then, the lower and upper bounds of the confidence interval are:

$LL=M_d-t \cdot s_{M_d} = 3-8.34=-5.34\\\\UL=M_d+t \cdot s_{M_d} = 3+8.34=11.34$

The 95% confidence interval for the difference between means is (-5.34, 11.34).

6 0

4 years ago

15 pts + brainliest to right/best answer

il63 [147K]

Split the second term in 5x^2 + 12 - 32 into two terms

5x^2 + 20x - 8x - 32

Factor out common terms in the first two terms, then in the last two terms

5x(x + 4) - 8(x + 4)

Factor out the common term: x + 4

7 0

3 years ago

Read 2 more answers

I’ll give brainliest!!!

Maslowich

14a. =

15b. 2/3 is less than 0.667

16c. 3 7/8 is greater than 3.375

17d. 3/8 is less than 1/2

6 0

3 years ago

What is 20% of $16.75? Explain please I really need help

Ilya [14]

Just multiply .20 x 16.75 = 3.35 If you want the percent of something just move the decimal place over to the left twice and multiply it by the given price

4 0

4 years ago

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How do you do this problem?

zhenek [66]

Answer:

A) g is increasing, and the graph of g is concave up.

Step-by-step explanation:

g'(x) = ∫₀ˣ e^(-t³) dt

Since e^(-t³) is always positive, ∫₀ˣ e^(-t³) dt is positive when x > 0. So the function is increasing.

Find g"(x) by taking the derivative using second fundamental theorem of calculus:

g"(x) = e^(-x³)

g"(x) is always positive, so the function is always concave up.

5 0

3 years ago