We consider the x- and y-coordinates separately. Let the coordinates of G be (x, y). Now considering the x-coordinates: FG/FH = (x - (-3)) / (-3 - (-3)) = 2/3 x + 3 = (2/3)(6) x = 1 For the y-coordinates: FG/FH = (y - 2) / (7 - 2) = 2/3 y - 2 = (2/3)(5) y = 16/3 Therefore the coordinates of G are (1, 16/3).