Answer:
<h3>Negative one-half (negative 2) (x + 3) = negative 10 (negative one-half)</h3>
Step-by-step explanation:
Given the expression
- 2 (x + 3) = - 10
The first step in solving the expression is to multiply both sides by -1/2 as shown;
-1/2(-2)(x+3) = -1/2(-10)
(x +3) = 1/2(10)
x + 3 = 5
x = 5-3
x = 2
Hence the correct option is Negative one-half (negative 2) (x + 3) = negative 10 (negative one-half)
Answer:- B , C and F are the right options.
Explanation:-
1. HA cannot be a reason to show given triangles are congruent as it is not given that they have an acute angle common in both the triangles.
2. HL can be a reason to show given triangles are congruent as the triangles are right triangle with equal legs and hypotenuse.
3. SAS can be a reason to show given triangles are congruent as there are two congruent sides in both triangles and included angles ∠A=∠D=90° [right angle].
4. LA cannot be a reason to show given triangles are congruent as it is not given that they have an acute angle common in both the triangles.
5. AAS cannot be a reason to show given triangles are congruent as it is not given that they have two angles common in both the triangles.
6.SSS can be a reason to show given triangles are congruent as it is shown that all the sides of one triangle is congruent to the other.
A.
You can subtract values that are being divided in Sin waves.
That depends. If you have a finite data set, you would add up all the points you have and divide by the total count.
Or, if you are working with pure distributions, the mean is the same as the expected value of the corresponding random variable.
Suppose you have a discrete random variable

with a given probability mass function

, then the mean is given by

which would mean you take all the possible probability for the event that

, multiply each by that

, and add them together.
If the distribution is continuous, say a random variable

that has probability distribution function

over some support

, then the mean is
9514 1404 393
Answer:
- minimum: 2 at x=0
- maximum: 10 at x=10
Step-by-step explanation:
When looking for extremes, one must consider both the turning points and the ends of the interval. Here, there is a relative minimum at x=7, and a relative maximum at x=3. However, the values at the ends of the interval are more extreme than these.
The absolute minimum on the interval is 2 at x=0.
The absolute maximum on the interval is 10 at x=10.