(x²+4x+3)/2(x²-10x+25)
the horizontal asymptote when the numerator and the denominator have the same degree (in this case, both of a degree of 2) is ration of the coefficients of the numerator and denominator. In this case, the coefficient for numerator x² is 1, and the coefficient for the denominator 2x² is 2, so the horizontal asymptote is y=1/2=0.5
the vertical asymptote is the x value. the denominator cannot be zero, if x²-10x+25=0, x would be 5, so the vertical asymptote is x=5
this is just one example. There can be others:
(2x²+5x+2)/[(4x-7)(x-5)] for another example, but this example has a second vertical asymptote 4x-7=0 =>x=7/4
Answer:
C. cot theta
Step-by-step explanation:
(csc theta -cot theta )/(sec theta -1)
csc = 1/ sin
cot = cos / sin
sec = 1 / cos
Let x = theta
(1/ sin x -cos x / sin x )/(1/ cos x -1)
Getting a common denominator in the denominator and combining terms
(1- cos x)/ sinx / ( 1 - cos x) / cos x
(1- cosx) (1- cosx)
----------- ÷ ------------
sinx cos x
Copy dot flip
(1- cosx) cosx
----------- * ------------
sinx 1 -cos x
Cancel like terms
cos x / sin x
cos / sin = cot
cot x
cot theta
Answer:
A.
Step-by-step explanation:
It has a negative slope, so B and C are eliminated. The graph also has a solid line instead of a dashed line. This means D is eliminated because it is only greater than. If the graph had a dashed line, then D would be correct, but it does not.
Answer:
Step-by-step explanation:
Given
<em>See attachment</em>
Required
Determine the area of K
First, we need to calculate the length of the rectangle J
This gives:
Divide both sides by 22
So, the length of the rectangle J is 20.
Since both shapes are similar, then:
Substitute the known values:
Express as fraction:
Make Length, the subject of formula
The area of K is:
Step-by-step explanation:
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