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xxTIMURxx [149]
3 years ago
13

Please help :( <3 I really need 100 so I could have a A in math please. ​

Mathematics
2 answers:
Brrunno [24]3 years ago
7 0

Answer:

B!

Step-by-step explanation:

Citrus2011 [14]3 years ago
7 0

Answer:

b

Step-by-step explanation:

If you look carefully at the answer choices you don't have a correct answer for  to take 3 blocks away from the left, but you do have the choice to add 3 to the right to make it even.

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I need help. ASAP. PLEASE.
Vlad1618 [11]
You haven’t supplied enough information to help you. The original question would have helped.
7 0
3 years ago
Figure out the pattern, fill in<br> the blank
zmey [24]

Answer:

384

Step-by-step explanation:

The pattern is: the sum of the multiplication of the 2 numbers underneath the blank.

48 * 8 = 384

Hope this helps! Please tell me if I did something wrong, thanks!

6 0
3 years ago
What is the domain of a graph below?​
Anna35 [415]

Answer:

-4,0

Step-by-step explanation:

5 0
3 years ago
At 6:00 a.m. there were 68 geese in the pond. At 7:30 a.m. There were 50 geese in
Nesterboy [21]

12 geese left per hour. At 7:30 am there were 18 less geese than there were at 6:00 am. Since there was 1.5 hours between each time, and we know that 2/3 of 1.5 hours is 1 hour, we can solve using this equation:

2/3 * 18 = 12.

4 0
3 years ago
A cannonball is shot into the air. Its height can be described by the equation H = -5t² + 40t, where “h” is the height in feet a
DedPeter [7]

Answer:

t = 8 seconds

Step-by-step explanation:

Since this is a quadratic equation, there will be two values for which H = 0, (the ball is on the ground), so we'll just solve the equation and the first value will be the moment when the cannonball is launched, and the other will be when the cannonball falls to the ground.

0 = -5t² + 40t

Factorizing, since the two terms are being multiplied by t:

t(40 - 5t) = 0

the equation is true whenever t = 0 or t = 8, so we know that at the zeroth second, the ball was being launched, and at the 8th second, the ball was on the ground.

Here is how the graph looks like:

5 0
4 years ago
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