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Elza [17]
3 years ago
13

I need help Please and Thank you. A fundraiser sells 150 candy bars for a total of $125. What was the unit price (price per cand

y bar)? A $1.25 C. $1.50 B. $1.20 D. $0.90​
Mathematics
1 answer:
Oliga [24]3 years ago
3 0
The answer is $1.20
Can I get Brainliest?
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Which data is considered a out liner 40,35, 44,90,23,25,28,35
lana66690 [7]
90 is the outlier
for future reference, outliers are numbers much larger or much smaller than the other numbers in a set
for example
2,3,4,21,6
or 90,87,94,12,99
7 0
3 years ago
Can someone help me fast pls
kykrilka [37]

Your answer would be C.) 18oz

5 0
2 years ago
Determine whether the points (–3,–2) and (3,2) are in the solution set of the system of inequalities below. y ≤ ½x + 2 y < –2
lana [24]

Given:

The system of inequalities:

y\leq \dfrac{1}{2}x+2

y

To find:

Whether the points (–3,–2) and (3,2) are in the solution set of the given system of inequalities.

Solution:

A point is in the solution set of the given system of inequalities if it satisfies both inequalities.

Check for the point (-3,-2).

-2\leq \dfrac{1}{2}(-3)+2

-2\leq -1.5+2

-2\leq 0.5

This statement is true.

-2

-2

-2

This statement is also true.

Since the point (-3,-2) satisfies both inequalities, therefore (-3,-2) is in the solution set of the given system of inequalities.

Now, check for the point (3,2).

2

2

2

This statement is false because 2>-9.

Since the point (3,2) does not satisfy the second inequality, therefore (3,2) is not in the solution set of the given system of inequalities.

7 0
3 years ago
Factor using the identity: a3 + b3 = (a + b)(a2 – ab + b2) 8z3 + 27
vivado [14]

Answer:  this is our required factor i.e.

8z^3+27=(2z+3)(4z^2-6z+9)

Explanation:

Since we have given that

8z^3+27

As we know the identity , which says that

a^3+b^3=(a+b)(a^2-ab+b^2)

So, we can use this here ,

8z^3+27=(2z)^3+3^3\\\\=(2z+3)((2z)^2-2z\times 3+3^2)\\\\=(2z+3)(4z^2-6z+9)

Hence this is our required factor i.e.

8z^3+27=(2z+3)(4z^2-6z+9)


7 0
3 years ago
Read 2 more answers
The city mayor wants to use the reserved section of a rectangular park for gardening lessons conducted by the city public school
Nezavi [6.7K]

Answer:

the answer is C (280 square feet)

Step-by-step explanation:

First, cut the lawn so that it becomes two shapes: a rectangle, and a triangle. Solve for both areas.

A(r) = lw

A(r) = (14)(16)

A(r) = 224 square feet

A(t) = bh/2

A(t) = (8)(14) / 2

A(t) = 112 / 2

A(t) = 56 square feet

Add the two areas:

A(r) + A(t) = Area of lawn

224 square feet + 56 square feet = 280 square feet.

7 0
3 years ago
Read 2 more answers
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