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3 years ago

Is -1/3 a rational number

Mathematics

2 answers:

Semenov [28]3 years ago

7 0

Answer:

-1/3 is a rational number

grin007 [14]3 years ago

4 0

Answer:

yes

Step-by-step explanation:

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Vilka [71]

Answer:

70,110,110,110

Step-by-step explanation:

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3 years ago

Please Help!!!......

valina [46]

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2 years ago

Karen Sullivan delivers newspapers for the Tribune dispatch. She receives 18.2 cents per paper, six days a week (for the daily p

mario62 [17]

Answer:

About $241.11

Step-by-step explanation:

So, Karen receives 18.2 cents per paper.

She delivers 124 paper per day.

In other words, on days other than Sunday, she will make a total of:

$18.2(124)=2256.8\text{ cents}$

On Sunday, each paper is sold for $0.70 or 70 cents. She also sells 151 Sunday papers. Thus, on a Sunday, she will make a total of:

$70(151)=10570\text{ cents}$

Therefore, in one week, she will do the first equation six times and the Sunday equation once. Thus, her total pay will be:

$6(2256.8)+10570=24110.8\text{ cents}\approx\$241.11$

4 0

3 years ago

Identify the polynomial. x3- y3 + z a)monomial b)binomial c)trinomial ...?

fomenos

In elementary algebra, a trinomial is a polynomial consisting of three terms or monomials.

8 0

3 years ago

Read 2 more answers

30+ Points!!! 5. Solve the following inequalities. a) 2 log3x – 2 logx3 -3 <0

Ilya [14]

Answer:

I answered your last question also

2 log3x – 2 logx3 -3 <0

$\mathrm{Subtract\:}2\log ^3\left(x\right)\mathrm{\:from\:both\:sides}$

$2\log ^3\left(x\right)-2logx^3-3-2\log ^3\left(x\right)$

$\mathrm{Simplify}$

$-2logx^3-3$

$\mathrm{Add\:}3\mathrm{\:to\:both\:sides}$

$-2logx^3-3+3$

$\mathrm{Simplify}$

$-2logx^3$

$Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)$

$\left(-2logx^3\right)\left(-1\right)>-2\log ^3\left(x\right)\left(-1\right)+3\left(-1\right)$

$\mathrm{Simplify}$

$2lx^3og>2\log ^3\left(x\right)-3$

$\mathrm{Divide\:both\:sides\:by\:}2lx^3o;\quad \:l>0$

$\frac{2lx^3og}{2lx^3o}>\frac{2\log ^3\left(x\right)}{2lx^3o}-\frac{3}{2lx^3o};\quad \:l>0\\$

$\mathrm{Simplify}$

$g>\frac{2\log ^3\left(x\right)-3}{2lx^3o};\quad \:l>0$

Step-by-step explanation:

6 0

3 years ago