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SpyIntel [72]
2 years ago
8

What is the answer about this I really need help

Mathematics
2 answers:
sergey [27]2 years ago
7 0

Answer:

hi

Step-by-step explanation:

Olenka [21]2 years ago
4 0

Answer:What's the question

Step-by-step explanation:

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The ratio of dogs to cats at a local animal shelter is 13/25. Which statement must be true?
Ivan

<em>Option:</em>

<em>a. for every 13 dogs, there are 25 cats. </em>

<em>b. there are twice as many cats as dogs at the shelter. </em>

<em>c. the shelter has more dogs than cats. </em>

<em>d. there are 25 animals in the shelter.</em>

Answer:

a. for every 13 dogs, there are 25 cats.

<em></em>

Step-by-step explanation:

Represent Dogs with D and Cats with C;

So;

\frac{D}{C} = \frac{13}{25}

By comparison:

D=13

C = 25

This implies that:

For every 13 D, there are 25 C

Hence: Option A is true

6 0
2 years ago
Which is the value of this expression when p = - 2 and q = -1?
Elan Coil [88]

Answer: -4 is the answer

Step-by-step explanation:

4 0
2 years ago
There are 2820 cars in Farmington. The ratio of medium size cars to compacts is 7 to 5 and the ratio of compacts to full-size ca
oee [108]

Answer:

Number of full size cars = 900

Step-by-step explanation:

The ratio of medium size cars to compacts is 7 to 5 and the ratio of compacts to full-size cars is 8 to 9. Since compact cars are  there in both ratios , we need to  make the number in the ratio for compact cars to be the same.

\frac{medium}{compact} = \frac{7}{5}

Multiply by 8 on numerator and denominator

\frac{medium}{compact} = \frac{56}{40}

\frac{compact}{full size} = \frac{8}{9}

Multiply numerator and denominator by 5.

\frac{compact}{full size} = \frac{40}{45}

Ratio of medium, compact and full size are in ratio 56,40,45.

Total number of cars =2820.

(56 + 40 + 45)x = 2820

x = \frac{2820}{141}

x = 20

Number of full size cars = 20\times 45 =900

3 0
3 years ago
I have a question about brainly
faltersainse [42]
I don’t think so, I may be wrong
8 0
3 years ago
Read 2 more answers
Use the laplace transform to solve the given initial-value problem. y' − 2y = (t − 4), y(0) = 0
yulyashka [42]

Using the Laplace transform, the value o y' − 2y = (t − 4), y(0) = 0 is⇒y(t) = 0 e^-t + u(t -1)e^1-t

Laplace rework is an critical rework approach that is in particular useful in fixing linear normal equations. It unearths very huge applications in  regions of physics, electrical engineering, control optics, arithmetic and sign processing.

y' − 2y = (t − 4),

y(0) = 0

Taking the Laplace transformation of the differential equation

⇒sY(s) - y (0) + Y(s) = e-s

⇒(s + 1)Y(s) = (0+ e^-s)/s + 1

⇒y(t) = L^-1{0/s+1} + {e ^-s/s + 1}

⇒y(t) = 0 e^-t + u(t -1)e^1-t

The Laplace remodel method, the feature within the time area is transformed to a Laplace characteristic within the frequency domain. This Laplace feature will be inside the shape of an algebraic equation and it can be solved easily.

Learn more Laplace transformation here:-brainly.com/question/14487437

#SPJ4

4 0
1 year ago
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