The answer is y=0
See the attached photo for details
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The external tangent is line s
Answer:
2x-1=x+1
2x-x=x
1+1=2
x=2
Knowing x's value, we substitute it with the equations
y=x+1
y=2+1
or y=2x-1
y=2(2)-1
y=4-1
y=3
(2,3) are your coordinates :D
Answer:
The perimeter of rectangle is 
Step-by-step explanation:
Let
x-----> the length of the rectangle
y----> the width of the rectangle
we know that
----> equation A
---> equation B (area of the constructed figure)
substitute the equation A in equation B
using a graphing calculator -----> solve the quadratic equation
The solution is
Find the value of x
Find the perimeter of rectangle
Y = 2x^2 - 13x + 5
dy/dx = 4x - 13
At x = 3, dy/dx = 4(3) - 13 = 12 - 13 = -1
and y = 2(3)^2 - 13(3) + 5 = 2(9) - 39 + 5 = 18 - 34 = -16
The tangent line at x = 3, passes through the point (3, -16) and has a slope of -1
y - (-16) = -1(x - 3)
y + 16 = -x + 3
y = -x - 13 is the required equation.
