Recall that one whole is 1, or in this case since the denominator is 4, then 4/4 is 1 whole, so the whole lawn is 4/4.
Answer:
Let's define all the possible forms:
slope-intercept: y = a*x + b
point-slope: y - y1 = a*(x - x1) (where (x1, y1) is a point in the line)
standard form: a*x + b*y = c
then:
a) 7x + 5y = 8
This is in standard form.
b) y − 5 = 3*(x − 9)
This is in point slope form.
c) y = 7x + 9
This is in slope-intercept form.
d) 8x − 9y = −2
This is in standard form.
Hyperbole is the correct answer
The answer for this problem would be : true
A quadratic equation is of the format:
ax² + bx + c = 0, where a ≠ 0.
The first option is not quadratic, it is a cubic, it has highest power of 3.
The second option f (x) = 3/4 x ^2 + 2x − 5, is quadratic, that is the answer.
The third f(x) = 4/x^2 - 2/x + 1, doesn't qualify because of the 2/x.
The last f(x) = 0x^2 − 9x + 7
, doesn't qualify because of the a = 0, and the rule is that a ≠ 0.
Therefore f (x) = 3/4 x ^2 + 2x − 5 represents a quadratic function.
I hope this helps.
