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Zanzabum
4 years ago
7

PLEASE HELP! Two joggers run 9 miles north then 3 miles west.What is the shortest distance, to the nearest tenth of a mile, they

must travel to return to their starting point?
Mathematics
1 answer:
Marysya12 [62]4 years ago
3 0

Answer:

9.4 miles

Step-by-step explanation:

5 ² +8 ² =C ²

25+64=c ²

89=c ²

c=9.4

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The cable provider's "triple play" package offers a land line, internet service, and cable TV for one fixed price. If you alread
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Answer:

$166.16, you would have to subtract 132 by 12% or .12 and would get 166.16 :)

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3 years ago
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A population is known to be normally distributed with a standard deviation of 2.8. (a) Compute the 95% confidence interval on th
Ugo [173]

Answer:

Step-by-step explanation:

Mean = sum of terms/number of terms

The mean of the given sample is

(8 + 9 + 10 + 13 + 14 + 16 + 17 + 20 + 21)/9 = 14.2

a)

For a confidence level of 95%, the corresponding z value is 1.96.

We will apply the formula

Confidence interval

= mean ± z ×standard deviation/√n

Where

n represents the number of samples

It becomes

14.2 ± 1.96 × 2.8/√9

= 14.2 ± 1.96 × 0.933

= 14.2 ± 1.83

The lower end of the confidence interval is 12.37

The upper end of the confidence interval is 16.03

b)

For a confidence level of 99%, the corresponding z value is 2.58

We will apply the formula

Confidence interval

= mean ± z ×standard deviation/√n

Where

n represents the number of samples

It becomes

14.2 ± 2.58 × 2.8/√9

= 14.2 ± 2.58 × 0.933

= 14.2 ± 2.4

The lower end of the confidence interval is 11.8

The upper end of the confidence interval is 16.6

3 0
3 years ago
What is 3.754×10^5 than round it to the tenth
saul85 [17]

Answer:

375,400

Step-by-step explanation:

  1. 3.754*10^5
  2. 10^5=100,000
  3. 3.754*100,000
  4. 375,400

YaYYYY u got it! =)

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3 years ago
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Klio2033 [76]
7/12 and 1/2
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3 years ago
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PLEASE HELP
oee [108]
3:1 ratio meaning for every 3 brown eyed people there are 1 blue eyed. So if you have 12 brown every you have 4 blue eyed. Giving you a total of 16 people.
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3 years ago
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