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Bingel [31]
3 years ago
5

What does the expression 1.5a + 2b represent

Mathematics
1 answer:
madreJ [45]3 years ago
8 0
Represents me getting points
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What is sn for the arithmetic series with a1=3 an=-38 and n=8?
otez555 [7]
Sn = n/2 (a1+an)
= 8/2 (3-38)
= 4 (-35)
= -140
4 0
3 years ago
Will give brainliest
algol [13]

Answer:

Step-by-step explanation:

-5x + 5

6 0
3 years ago
2. How many real number solutions are there to the equation 0 =-3x2 + x - 4?
goblinko [34]

For this case we have the following quadratic equation:

-3x ^ 2 + x-4 = 0

Where:

a = -3\\b = 1\\c = -4

By definition, the discriminant of a quadratic equation is given by:

d = b ^ 2-4 (a) (c)

We have to:

d> 0: Two different real roots

dTwo different complex roots

d = 0: Two equal real roots

Substituting the values we have:

d = 1 ^ 2-4 (-3) (- 4)\\d = 1-48\\d = -47

So, we have two different complex roots

Answer:

Two different complex roots

7 0
3 years ago
Write an equation for a line parallel to y=-3x+2 that passes through the point (-1,4)
Wewaii [24]

<span>y=−3x+2</span> is a linear equation in slope-intercept form with
slope <span>m=<span>(−3)</span></span>
(and y-intercept <span>=2</span>)

We want the equation of a line with slope <span>m=<span>(−3)</span></span> through the point <span>(<span>−2</span>,<span>−8</span>)</span>

Using the point-slope linear equation form:
<span><span>(y−<span>(−8)</span>)</span>=<span>(−3)</span><span>(x−<span>(−2)</span>)</span></span>

Simplifying
<span>y+8=−3x−6</span>
or, in standard form
<span>3x+y=−<span>14</span></span>

3 0
3 years ago
The American Management Association is studying the income of store managers in the retail industry. A random sample of 49 manag
VashaNatasha [74]

Answer:

a) The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

b) The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

Step-by-step explanation:

Question a:

We have to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a p-value of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{2050}{\sqrt{49}} = 574

The lower end of the interval is the sample mean subtracted by M. So it is 45420 - 574 = $44,846.

The upper end of the interval is the sample mean added to M. So it is 45420 + 574 = $45,994.

The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

Question b:

The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

5 0
3 years ago
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