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tamaranim1 [39]
2 years ago
14

A spinner is divided into 15 identical sectors and labeled 1 through 15. how many spins are expected for a multiple of 4 to be s

pun 30 times? select from the drop-down menu to correctly complete the sentence. the spinner is expected to have to spin approximately a) 113 b) 120 c) 150 d) 225 times for a multiple of 4 to be spun 30 times.
Mathematics
2 answers:
DanielleElmas [232]2 years ago
5 0
Answer: 150 took test



oee [108]2 years ago
4 0

The spinner is expected to have to spin approximately 150  times for a multiple of 4 to be spun 30 times.

if you could give me brainliest i would greatly appreciate it

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Write the divisor of 4/12=1/3
mars1129 [50]
<span>4/12=3/9=2/6=1/3 </span>should be the right answer. (You have to reduce.)
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The rectangle has a length of (x+3) and the width (x+1)
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Use powers to rewrite these problems: Example: 5 x 5 = 52
jeyben [28]

Answer:

<u>Problem A</u>

5 * 5 * x * x * x

5^2*x^3

<u>Problem B</u>

8 * 8 * 8

8^3

<u>Problem C</u>

4 * 4 * 4 * x * x * x * x

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3 years ago
Find y when x=12 if y=15 when x=3
larisa [96]
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4 0
3 years ago
What's the next number? 0 , 1/3 , 1/2 , 3/5 , 2/3​
madam [21]

Answer:

The next number of the series 0, 1/3, 1/2, 3/5, and 2/3 is 5/7

Step-by-step explanation:

The given numbers are;

0, 1/3, 1/2, 3/5, and 2/3

The number sequence is formed adding \dfrac{1}{\left (\dfrac{n^2 + n}{2} \right ) } to each (n - 1)th term to get the nth term number in the sequence, with the first term equal to 0, as follows;

For the 2nd term, the (n - 1)th term is 0, and n = 2, gives;

The

0 +\dfrac{1}{\left (\dfrac{2^2 + 2}{2} \right ) } = 0 + \dfrac{1}{3} = \dfrac{1}{3}

For the 3rd term, the (n - 1)th term is 1/3, and n = 3, gives;

\dfrac{1}{3} +\dfrac{1}{\left (\dfrac{3^2 + 3}{2} \right ) } = \dfrac{1}{3} + \dfrac{1}{6} = \dfrac{1}{2}

For the 4th term, the (n - 1)th term is 1/2, and n = 4, gives;

\dfrac{1}{2} +\dfrac{1}{\left (\dfrac{4^2 + 4}{2} \right ) } = \dfrac{1}{2} + \dfrac{1}{10} = \dfrac{3}{5}

For the 5th term, the (n - 1)th term is 3/5, and n = 5, gives;

\dfrac{3}{5} +\dfrac{1}{\left (\dfrac{5^2 + 5}{2} \right ) } = \dfrac{3}{5} + \dfrac{1}{15} = \dfrac{2}{3}

For the next or 6th term, the (n - 1)th term is 2/3, and n = 6, gives;

\dfrac{2}{3} +\dfrac{1}{\left (\dfrac{6^2 + 6}{2} \right ) } = \dfrac{2}{3} + \dfrac{1}{21} =  \dfrac{15}{21} = \dfrac{5}{7}

The next number of the series 0, 1/3, 1/2, 3/5, and 2/3 = 5/7.

6 0
3 years ago
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