Answer:
![\sf \Bigg[ \frac{ ( - 4 \times ( - 3)) }{2} \Bigg] \: and \: \Bigg[ \frac{ - ( - 5 \times 8)}{10} + 2 \Bigg]](https://tex.z-dn.net/?f=%20%20%20%5Csf%20%5CBigg%5B%20%5Cfrac%7B%20%28%20-%204%20%5Ctimes%20%28%20-%203%29%29%20%7D%7B2%7D%20%5CBigg%5D%20%5C%3A%20and%20%20%5C%3A%20%5CBigg%5B%20%5Cfrac%7B%20-%20%28%20-%205%20%5Ctimes%208%29%7D%7B10%7D%20%2B%202%20%5CBigg%5D)
Step-by-step explanation:
Given:
To find:
Two expressions that equal 6 using the given numbers
Solution:
Expression first,
Using numbers -4, 2, -3,
aligning the above numbers as,
will out put 6.
<em>Verification,</em>
Expression second,
Using numbers 10,8,2,-5
aligning the above numbers as,
will result 6.
<em>Verification</em>
<em><u>Thanks for joining brainly community!</u></em>
We can then write an equation representing this problem as:
e−1.5mi=5.25mi
Now, add 1.5mi to each side of the equation to solve for e while keeping the equation balanced:
e−1.5mi+1.5mi=5.25mi+1.5mi
e−0=6.75mi
e=6.75mi
The plane's starting elevation was 6.75 miles
Hope this helps!
To justify the yearly membership, you want to pay at least the same amount as a no-membership purchase, otherwise you would be losing money by purchasing a yearly membership. So set the no-membership cost equal to the yearly membership cost and solve.
no-membership costs $2 per day for swimming and $5 per day for aerobic, in other words, $7 per day. So if we let d = number of days, our cost can be calculated by "7d"
a yearly membership costs $200 plus $3 per day, or in other words, "200 + 3d"
Set them equal to each other and solve:
7d = 200 + 3d
4d = 200
d = 50
So you would need to attend the classes for at least 50 days to justify a yearly membership. I hope that helps!
Answer:
385 golf balls
Step-by-step explanation:
margin of error = (z*)(s) / sqrt n
where z* = 1.96 with 5%/ 2 = 0.025 area in each tail
margin of error = (z*)(s) / sqrt n
1.2 yards = (1.96)(12 yards) / sqrt n
solve for n
n = 384.16
385 golf balls (always round up)
Answer:
Present age
Son: 15
Father: 45
Step-by-step explanation:
Remark
Thank you for the translation. Without it, the problem would be impossible -- at least for me.
Givens
Let the present age of the father = x
Let the present age of the son = y
Solution
x + y = 60
How many years will pass? You could say it's z.
x + z = y When z years pass, the son will be his father's present age.
x + z + y + z = 120 when z is added to both their current ages, the result is 120 Collect like terms
x + y + 2z = 120
<u>x + y = 60 </u> Subtract The very first equation
2z = 60 Divide by 2
z = 60/2 30 years have passed.
z = 30
x + z = y
x + 30 = y Substitute x + 30 for the present y value (the father).
x + x + 30 = 60
2x = 30
x = 15
x + y = 60
15 + y = 60
y = 60 - 15
y = 45
So the son's age right now is 15
The father's age right now is 45
