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2 years ago

6

Can someone pls help me I’m stuck

2 answers:

scZoUnD [109]2 years ago

6 0

Answer:

i am sorry i have no idea sorry

djyliett [7]2 years ago

6 0

Answer: B

Step-by-step explanation: Hope this help :D

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lukranit [14]

Answer:

y - 4 = 3(x- (-1) ---> y-4 = 3(x+1)

Step-by-step explanation:

y - 4 = 3(x + 1)

y - 4 = 3x + 3

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then plug in (-1,4)

4 = 3(-1) + 7

4 = -3 + 7

4 = 4

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y - y₁ = m(x - x₁)

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A fitness center runs a contest for customers who enroll in its annual membership plan. The customers are allowed to draw a coup

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2 years ago

Read 2 more answers

A president, treasurer, and secretary, all di erent, are to be chosen from a club consisting of 12 people (whose names are I, J,

Ierofanga [76]

Answer:

There are 220 choices

Step-by-step explanation:

Given

$People = 12$

$Selection =3$ (President, Treasurer and Secretary)

Required

Determine number of selection (if no restriction)

This is calculated using the following combination formula:

$^nC_r = \frac{n!}{(n - r)!r!}$

Where

$n = 12$

$r= 3$

So, we have:

$^nC_r = \frac{n!}{(n - r)!r!}$

$^{12}C_3 = \frac{12!}{(12 - 3)!3!}$

$^{12}C_3 = \frac{12!}{9!3!}$

$^{12}C_3 = \frac{12*11*10*9!}{9!3!}$

$^{12}C_3 = \frac{12*11*10}{3!}$

$^{12}C_3 = \frac{12*11*10}{3*2*1}$

$^{12}C_3 = \frac{12*11*10}{6}$

$^{12}C_3 = 2*11*10$

$^{12}C_3 = 220\ ways$

<em>There are 220 choices</em>

8 0

2 years ago