Answer:
(x, y) = (2, 5)
Step-by-step explanation:
I find it easier to solve equations like this by solving for x' = 1/x and y' = 1/y. The equations then become ...
3x' -y' = 13/10
x' +2y' = 9/10
Adding twice the first equation to the second, we get ...
2(3x' -y') +(x' +2y') = 2(13/10) +(9/10)
7x' = 35/10 . . . . . . simplify
x' = 5/10 = 1/2 . . . . divide by 7
Using the first equation to find y', we have ...
y' = 3x' -13/10 = 3(5/10) -13/10 = 2/10 = 1/5
So, the solution is ...
x = 1/x' = 1/(1/2) = 2
y = 1/y' = 1/(1/5) = 5
(x, y) = (2, 5)
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The attached graph shows the original equations. There are two points of intersection of the curves, one at (0, 0). Of course, both equations are undefined at that point, so each graph will have a "hole" there.
1) slope-2/3, y-intercept-(0,6)
2) slope- -2/3, y-intercept-(0,-3)
3) slope- 8, y-intercept-(0,-6)
4) slope- 6, y-intercept-(0,-8)
The polygons are similar.
This is because dividing the corresponding sides forms the same ratio, as shown by the three equations below
35/28 = 1.25
25/20 = 1.25
(15.5)/(12.4) = 1.25
So the larger figure on the right has side lengths that are 1.25 times larger compared to the corresponding sides of the figure on the left.
You'll need to flip the figure on the left so that the side labeled "20" is along the top, and the "28" is along the bottom.
After this flip happens, also note that the angle arc markings match up. The bottom pairs of angles of each figure are shown with a single arc, while the top angles are shown as double arcs. This helps visually show which angles pair up and are congruent to one another.
Because we have similar proportions as discussed earlier, and congruent pairs of angles like this, this shows the two figures are similar quadrilaterals. The one on the right is simply an enlarged scaled up copy of the figure on the left.
Answer:
$40.39x
Step-by-step explanation:
hope this helpss!!!
