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3 years ago

What is the zero of (-8,-1) and (4,2)

Mathematics

1 answer:

lukranit [14]3 years ago

5 0

Answer:

It’s 4.2

Step-by-step explanation:

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Which measurements are for a rectangle with an area of 16 square units?

Hoochie [10]

Answer:

This would be length = 4 and width = 4

Step-by-step explanation:

This is because to find the area of a rectangle its length x width.

So the two numbers that multiply to 16 is 4 and 4.

If you have any questions feel free to ask in the comments - Mark

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3 years ago

What is x=g/b2-4ac/2a

Alexandra [31]

Hello there!

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3 years ago

What is f (x)=2x^2+5 multiplied by g (x)=2x A) 7x+2x B) 4x+10x C)4x^2+10x D)4x^3+10x

Afina-wow [57]

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3 years ago

he ratio of your monthly allowance to your friend’s monthly allowance is 5 : 3. Both of your monthly allowances total $40. How m

Elena-2011 [213]

Answer:

your allowance is $25 and your friends is $15

Step-by-step explanation:

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3 years ago

Read 2 more answers

Use Stokes' Theorem to evaluate C F · dr F(x, y, z) = xyi + yzj + zxk, C is the boundary of the part of the paraboloid z = 1 − x

Serggg [28]

I assume $C$ has counterclockwise orientation when viewed from above.

By Stokes' theorem,

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

so we first compute the curl:

$\vec F(x,y,z)=xy\,\vec\imath+yz\,\vec\jmath+xz\,\vec k$

$\implies\nabla\times\vec F(x,y,z)=-y\,\vec\imath-z\,\vec\jmath-x\,\vec k$

Then parameterize $S$ by

$\vec r(u,v)=\cos u\sin v\,\vec\imath+\sin u\sin v\,\vec\jmath+\cos^2v\,\vec k$

where the $z$ -component is obtained from

$1-(\cos u\sin v)^2-(\sin u\sin v)^2=1-\sin^2v=\cos^2v$

with $0\le u\le\dfrac\pi2$ and $0\le v\le\dfrac\pi2$ .

Take the normal vector to $S$ to be

$\vec r_v\times\vec r_u=2\cos u\cos v\sin^2v\,\vec\imath+\sin u\sin v\sin(2v)\,\vec\jmath+\cos v\sin v\,\vec k$

Then the line integral is equal in value to the surface integral,

$\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

$=\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}(-\sin u\sin v\,\vec\imath-\cos^2v\,\vec\jmath-\cos u\sin v\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle-\int_0^{\pi/2}\int_0^{\pi/2}\cos v\sin^2v(\cos u+2\cos^2v\sin u+\sin(2u)\sin v)\,\mathrm du\,\mathrm dv=\boxed{-\frac{17}{20}}$

6 0

3 years ago

What is the zero of (-8,-1) and (4,2)​

What is the zero of (-8,-1) and (4,2)