Answer:
f
Step-by-step explanation:
Answer:
The time interval when 
is at 
The distance is 106.109 m
Step-by-step explanation:
The velocity of the second particle Q moving along the x-axis is :
So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.
We are also to that :
between 
The schematic free body graphical representation of the above illustration was attached in the file below and the point when is at 4 is obtained in the parabolic curve.
So, is at
Taking the integral of the time interval in order to determine the distance; we have:
distance = 
= 
= By using the Scientific calculator notation;
distance = 106.109 m
Answer:
26+38 that should be the answer for it
Answer:
6
Step-by-step explanation:
The overbar means the digit repeats indefinitely. The repeating decimal 0.333... is equivalent to 1/3, so this is the simple addition ...
3 2/3 + 2 1/3 = 5 3/3 = 6
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<em>Comment on the repeating decimal</em>
1/3 = 0.3333... repeating is one of the first decimal equivalents you learn.
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If you're into repeating decimals. you may have learned how to convert them to fractions:
x = 0.3333... repeating . . . . . . . give a name to the value
10x = 3.3333... repeating . . . . . multiply by 10^p where p is the number of digits in the repeating pattern
10x - x = 3.3333... - 0.3333... = 3 . . . . . subtract: the repeating portions cancel
9x = 3 . . . . . . . . . .simplify
x = 3/9 = 1/3 . . . . .divide by the x-coefficient; simplify
