2(2y^4 + 7y^3 - 4y^2 -20)
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Y^2
4y^2 - 40/y^2 + 14y - 8
2(-2y^4 - 7y^3 + 4y^2 + 20)
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Y^2
Answer:answer is 387
Step-by-step explanation:ok got it
Answer:
{HH, HT, TH, TT}
Step-by-step explanation:
The set of all possible outcomes in tossing a coin twice is;
{HH, HT, TH, TT}
In the first toss the coin may land Heads. In the second toss the coin may land Heads or Tails. This can be represented as;
HH, HT
Heads in the first and second tosses. Heads in the first toss followed by a Tail in the second toss.
In the first toss the coin is also likely to land Tails. In the second toss the coin may land Heads or Tails. This can be represented as;
TH, TT
Tails in the first toss followed by a Head in the second toss. Tails in the first and second tosses.
Combining these two possibilities will give us the set of all possible outcomes in tossing a coin twice is;
{HH, HT, TH, TT}
Answer:
The other leg is 6 and the Hypotenuse is 6√2
Step-by-step explanation:
because it's a 45 45 90 the legs equal and the Hypotenuse is square root 2 times leg
f(5) is -1
Step-by-step explanation:
- Step 1: Given f(x) = -2x + 9, find f(5)
f(5) = -2 × 5 + 9 = -10 + 9 = -1
