All categories

3 years ago

Can somebody help me? h(x)=9*(2/3)^x

Mathematics

1 answer:

sergeinik [125]3 years ago

3 0

Answer:

Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote is y = 0 .

Horizontal Asymptote: y = 0

Step-by-step explanation:

x y

-2 81/4

-1 27/2

0 9

1 6

2 4

You might be interested in

In order to set rates, an insurance company is trying to estimate the number of sick days that full-time workers at an auto repa

kotegsom [21]

Answer: 31

Step-by-step explanation:

Formula to find the sample size is given by :_

$n=(\dfrac{z^*\cdot \sigma}{E})^2$

, where z*= critical value corresponds to confidence level.

$\sigma$ = population standard deviation.

E= Margin of error.

As per given , we have

$\sigma=2.8$

E=1

We know that critical value corresponding to 95% confidence level = z*=1.96

Then, the required sample size would be :

$n=(\dfrac{(1.96)\cdot (2.8)}{1})^2$

$n=(5.488)^2$

$n=30.118144\approx31$

Hence, the required minimum sample size = 31

3 0

4 years ago

Pls help 100 points also brainliest

just olya [345]

Answer:

C is the answer

Step-by-step explanation:

hope this helps

6 0

2 years ago

Read 2 more answers

the scale on a road map indicates that 2 inches equal 30 miles how many inches would represent 120 miles on this road map?

shtirl [24]

It would be 6 inches

7 0

3 years ago

Read 2 more answers

For 7-15, factor each expression. (if it cant be, then put CBF)(if you dont know it, please dont bother.)

Helen [10]

Answer:

-8

Step-by-step explanation:

7-7=0 remainder is 8 so minus 8 to zero -8

3 0

3 years ago

Read 2 more answers

What is the upper and lower quartile of 84-84 92 92 95 94 80-72

astra-53 [7]

Answer:

Upper Quartile / Q1 = 82

Lower Quartile / Q3 = 93

Step-by-step explanation:

The data we are given with is :

84 84 92 92 95 94 80 72

Let us first arrange the data in ascending order

72 80 84 84 92 92 94 95

The Formula to find the Quartile is

Quartile For Q1/Upper

$\frac{1}{4}\times(n+1)$ term

n=8

$\frac{1}{4}\times(8+1)$ term

$\frac{9}{4}$ term

2.25 term

This means that Quartile for Q1 is average of 2nd and 3rd term

2nd term = 80 , 3rd term = 84

Average = $\frac{80+84}{2}$

= 82

Quartile For Q3/Lower Quartile

$\frac{3}{4}\times(n+1)$ term

n=8

$\frac{3}{4}\times(8+1)$ term

$\frac{3 \times 9}{4}$ term

= 6.75

Hence the Quartile for Q3 will be the average of the 6th and 7th term

6th term = 92

7th term = 94

Average= $\frac{92+94}{2}$

= 93

Hence Upper Quartile / Q1 = 82

Lower Quartile / Q3 = 93

6 0

3 years ago