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3 years ago

Pls help i give brainliest if u answer early and good

Mathematics

1 answer:

Andre45 [30]3 years ago

8 0

Answer:

1 - BC = 5

2 - 174 (I think, im pretty sure tho)

3- 107

Step-by-step explanation:

Lets be real chief, you aren't here to learn. Ur taking test

Also, I got those numbers based on the images. The pic was kind of blurry

You might be interested in

The surface area of a rectangular prism is 35 square inches. What is the surface area of a similar solid with dimensions that ha

mario62 [17]

Answer:

$1,715\ in^{2}$

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its surface areas is equal to the scale factor squared

Let

z-----> the scale factor

x-----> surface area of the enlarged figure

y----> surface area of the original figure

$z^{2}=\frac{x}{y}$

we have

$z=7$

$y=35\ in^{2}$

substitute

$7^{2}=\frac{x}{35}$

$x=7^{2}(35)=1,715\ in^{2}$

8 0

3 years ago

How do these numbers compare?<br><br><br><br> 8.235 <br><br> 8.1

grigory [225]

Answer:

As we look at the 2 numbers, we see a 2 and a 1 in the tenths places, 2 is greater than 1.

Therefore, 8.235 > 8.1

Best of Luck to you.

8 0

3 years ago

What is the area of parallelogram rstu? 21 square units 24 square units 28 square units 32 square units

Ray Of Light [21]

The area of the considered parallelogram RTSU is given by: Option A: 21 sq. units

<h3>How to find the area of a parallelogram?</h3>

Area of a parallelogram = (its height × its base) sq. units.

<h3>What is the distance between two points ( p,q) and (x,y)?</h3>

The shortest distance(length of the straight line segment's length connecting both given points) between points ( p,q) and (x,y) is:

$D = \sqrt{(x-p)^2 + (y-q)^2} \: \rm units$

For this case, the missing diagram is attached below.

If we take the base as ST then as ST is parallel to y axis, the line perpendicular to ST would be parallel to x axis. The heigth of a parallogram is the perpendicular distance between its base and top.

The base is ST and top is RU, the line segment US is perpendicular to both RU and US and its length,therefore, will serve as height as its length=perpendicular distance between the base and the top of the parallelogram.

Thus, we get:

Area of RTSU = Length of ST × Length of US

The coordinates of endpoints of ST are (4,-1), (4,-4)

Thus, the length of ST = distance between S and T = $\sqrt{(4-4)^2 + (-1 - (-4))^2 }= 3$