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2 years ago

What is the square root of

1 answer:

5 0

Sq rt of 8464= 92
sq rt of 29584= 172
sq rt of 15376= 124
sq rt of 10816 = 104
sq rt of 21904 = 148
sq rt of 44100= 210
We call these perfect squares.

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What is the slope of the line

Nady [450]

Answer:

the slope is -2

Step-by-step explanation:

(1,0) (0,2)

$\frac{y2 - y1}{x2 - x1}$

[tex] \frac{2 - 0}{0 - 1} = - \frac{2}{ 1} = -2/tex]

7 0

2 years ago

A pilot can fly 2100 miles with the wind in the same time she can fly 1890 miles against the wind. If the speed of the wind is 2

Anna007 [38]

Answer:

475 mph

Step-by-step explanation:

Distance = rate × time

time = distance / rate

If x is the speed of the plane in still air:

2100 / (x + 25) = 1890 / (x − 25)

Cross multiply:

2100 (x − 25) = 1890 (x + 25)

Distribute and solve:

2100x − 52500 = 1890x + 47250

210x = 99750

x = 475

5 0

3 years ago

The number of minutes that Samantha waits to catch the bus is uniformly distributed between 0 and 15 minutes. What is the probab

Drupady [299]

Using the uniform distribution, it is found that there is a 0.3 = 30% probability that Samantha has to wait less than 4.5 minutes to catch the bus.

<h3>What is the uniform probability distribution?</h3>

It is a distribution with two bounds, a and b, in which each outcome is equally as likely.

The probability of finding a value of at lower than x is:

$P(X < x) = \frac{x - a}{b - a}$

In this problem, the time is uniformly distributed between 0 and 15 minutes, hence the bounds are a = 0 and b = 15.

The probability that Samantha has to wait less than 4.5 minutes to catch the bus is given by:

$P(X < 4.5) = \frac{4.5 - 0}{15 - 0} = 0.3$

More can be learned about the uniform distribution at brainly.com/question/13889040

7 0

2 years ago

A 2×n2×n checkerboard is to be tiled using two types of tiles. the first tile is a 1×11×1 square tile. the second tile is called

DiKsa [7]

The answer to your question is 34-12/76+56

6 0

3 years ago

Sunspots have been observed for many centuries. Records of sunspots from ancient Persian and Chinese astronomers go back thousan

Lunna [17]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41

Alternate Hypothesis, $H_A$ : $\mu$ > 41

(b) The value of z test statistics is 1.08.

(c) We conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

Step-by-step explanation:

We are given that in a random sample of 40 such periods from Spanish colonial times, the sample mean is x¯ = 47.0. Previous studies of sunspot activity during this period indicate that σ = 35.

It is thought that for thousands of years, the mean number of sunspots per 4-week period was about µ = 41.

Let $\mu$ = mean sunspot activity during the Spanish colonial period.

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41 {means that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41}

Alternate Hypothesis, $H_A$ : $\mu$ > 41 {means that the mean sunspot activity during the Spanish colonial period was higher than 41}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean = 47

σ = population standard deviation = 35

n = sample of periods from Spanish colonial times = 40

So, the test statistics = $\frac{47-41}{\frac{35}{\sqrt{40} } }$

= 1.08

(b) The value of z test statistics is 1.08.

(c) Now, the P-value of the test statistics is given by;

P-value = P(Z > 1.08) = 1 - P(Z < 1.08)

= 1 - 0.8599 = 0.1401

Since, the P-value of the test statistics is higher than the level of significance as 0.1401 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

8 0

3 years ago