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Anarel [89]
2 years ago
7

What is the square root of

Mathematics
1 answer:
Veronika [31]2 years ago
5 0
Sq rt of 8464= 92
sq rt of 29584= 172
sq rt of 15376= 124
sq rt of 10816 = 104
sq rt of 21904 = 148
sq rt of 44100= 210
We call these perfect squares.
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What is the value of 5.4?
Galina-37 [17]
The value is .54 hope this helped
5 0
3 years ago
Please help due today
vekshin1
The answer is 21 m squared
3(5)=15
3(2)=6
15+6=21
5 0
2 years ago
Read 2 more answers
11. Is the fraction 1/3 equivalent to a terminating
snow_tiger [21]

Answer:

It is equivalent to a decimal that does not terminate.

Step-by-step explanation:

When you divide 1 by 3, you get 0.33333333333333333333333333333333333333333333333333333 forever. The decimal never ends.

4 0
3 years ago
Solve for x. 2 1/2x−3/4(2x+5)=3/8
RUDIKE [14]
2 \frac{1}{2}x- \frac{3}{4}(2x+5)= \frac{3}{8}
2 \frac{1}{2}x- \frac{6}{4}x- \frac{15}{4}= \frac{3}{8}
( 2\frac{1}{2}- \frac{6}{4})x= \frac{3}{8}+ \frac{15}{4}
( \frac{5}{2}- \frac{6}{4})x= \frac{3}{8}+ \frac{15}{4}
( \frac{10}{4}- \frac{6}{4})x= \frac{3}{8}+ \frac{30}{8}
\frac{4}{4}x= \frac{33}{8}
x= \frac{33}{8}=4 \frac{1}{8}

Correct answer: C
6 0
3 years ago
Jess has 60 ounces of an alloy that is 40% gold. How many ounces of pure gold must be added to this alloy to create a new alloy
tia_tia [17]

Answer:

84 ounces of pure gold

Step-by-step explanation:

Jess has 60 ounces of an alloy that is 40% gold. How many ounces of pure gold must be added to this alloy to create a new alloy that is 75% gold?

Pure gold = 100% gold

Let the number of ounces of pure gold = x

Hence, we have the equation

40% × 60 ounces + 100%× x ounces = 75%(60 + x)ounces

= 0.4 × 60 + 1x = 0.75(60 + x)

= 24 + x = 45 + 0.75x

Collect like terms

x - 0.75x = 45 - 24

0.25x = 21

x = 21/0.25

x = 84 ounces

Therefore, we need 84 ounces of pure gold

6 0
3 years ago
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