2x + 4y = 8
x + 2y = 3
3x + 6y = 11
the answer for this question is x=4
A = base side=3
b= base side=5
c = base side=3
h= height=7-4=3
l= lenght=6
w= width=5
h= height=4
V= 1/4h√(-a⁴+2(ab)²+2(ac)²-b⁴+2(bc)²-c⁴) + l w h
V=12.44+ 120=132.44 unit³
<span>Let n = the number of nickles
Let q = the number of quarters
Then for your problem we have
(1) n + q = 43 and
(2) 5*n + 25*q = 100*6.95 (always work in cents to avoid decimal numbers) or
(3) 5*n + 25*q = 695
Now substitute n of (1) into (3) and get
(4) 5*(43 - q) + 25*q = 695 or
(5) 215 - 5*q + 25*q = 695 or
(6) 20*q = 695 - 215 or
(7) 20*q = 480 or
(8) q = 24
Then using (1) we get
(9) n + 24 = 43 or
(10) n = 19
Let's check these values.
Is (.05*19 + .25*24 = 6.95)?
Is (.95 + 6.00 = 6.95)?
Is (6.95 = 6.95)? Yes
Answer: Kevin and Randy have 19 nickles and 24 quarters in the jar.</span>
