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3 years ago

Solve this system of equations using elimination with multiplication

Mathematics

1 answer:

romanna [79]3 years ago

5 0

Answer:

Step-by-step explanation:

3x - 4y = -11

x - 2y = -5

Compare the coefficients of the variables.

The coefficients of the x terms, 3 and 1, are multiples of each other.

The coefficients of the y terms, -4 and -2, are also multiples of each other.

That makes it easy to eliminate either variable.

I'll eliminate the y variables. Multiply the second equation by -2, then add it to the first equation:

₋-2x + 4y = 10

3x - 4y = -11

--------------------

x + 0y = -1 , so x = -1.

Substitute -1 for x in either equation and solve for y:

3(-1) - 4y = -11

y = 2

(x,y) = (-1, 2)

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Read 2 more answers

What is the simplified form of <br><br> (X/3-y/4)/(x/4+y/3) ? (6 points)

Fofino [41]

Option 2: $\frac{4x-3y}{3x+4y}$ is the right answer

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$\frac{\frac{x}{3}-\frac{y}{4}}{\frac{x}{4}+\frac{y}{3}}$

To solve the fraction, Taking LCM in denominator and numerator

$=\frac{\frac{4x-3y}{12} }{\frac{3x+4y}{12}}$

When the numerator and denominator both have fractions, the simplified form is obtained be multiplying the numerator with reciprocal of the denominator. So,

$= \frac{4x-3y}{12} * \frac{12}{3x+4y}\\=\frac{4x-3y}{3x+4y}$